If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
Step-by-step explanation:
1. volume of a cylinder = pi x radius squared x height (I wasn't sure which was the radius/diameter)
2. 615.74
3. 1km
4. rearrange formula for volume of the cylinder to get the radius on 1 side. divide both sides by height and pi to leave u with r². then divide by the square root.
formula= r=square root of 3080³/3.14 × 20
5. height = volume/ pi x radius squared
6. 2463.01
7. 28.01
8. 145.955 m
9. 21.01
10. 17
You didn't include a picture of the answer choices, but this is what the answer would look like. Pretend the different shapes represent different rows:
ΔΔΔΔ
ββββ
αααα
There are three rows. 4 Books in each row.
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
Answer:
9348283848384848383838482
