Well, if it starts on 11:00 am, add 4 hours = 3:00 + 5 min = end time = 3:05 am.
Hopes this helps ;)
Equivalent Fractions for 9/25:
9/25, 18/50, 27/75, 36/100, 45/125, 54/150, 63/175, 72/200, 81/225, 90/250, and so on ...
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
X=0.697
x=4.30
Hope this helps