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ad-work [718]
3 years ago
6

WILL MARK AS BRAINLIEST 4. Suppose there is a card game where you are dealt a hand of three cards. You have already learned that

the total number of three-card hands that can be dealt from a deck of 52 cards is: 52C3=52!/49!3! 52C3=22100 Calculate the probability of getting a hand that has exactly two aces in it (A A X). Do this by finding out the number of possible hands that have exactly two aces, and then dividing by the total possible number of three-card hands that is stated above. Part A: Use the multiplication principle to tell the total number of three-card hands (permutations) that can be made with two aces. (2 points) Part B: In the answer from Part I, each two-ace hand got counted twice. For example, A A X got counted as a separate hand from A A X. Since order should not matter in a card hand, these are really the same hand. What is the actual number of two-ace hands (combinations) you can get from a deck of 52 cards?(2 points) Part C: Find the probability of drawing a three-card hand that includes two aces from a deck of 52 cards. Write your answer as a fraction. (2 points)
Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0

Answer:

Part A- 6

Part B- 3

Part C- 3/22100

Step-by-step explanation:

Part A-

Use the permutation formula and plug in 3 for n and 2 for k.

nPr=n!/(n-k)!

3P2=3!/(3-2)!

Simplify.

3P2=3!/1!

3P2=6

Part B-

Use the combination formula and plug in 3 for n and 2 for k.

nCk=n!/k!(n-k)!

3C2=3!/2!(3-2)!

Simplify.

3C2=3!/2!(1!)

3C2=3

Part C-

It is given that the total number of three-card hands that can be dealt from a deck of 52 cards is 22100. Use the fact that the probability of something equals the total successful outcomes over the sample space. In this case the total successful outcomes is 3 and the sample space is 22100.

I believe the answer is 3/22100

I honestly suck at probability but I tried my best.

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Find the product -2X²×4X²y²​
nydimaria [60]

Answer:

-8X^4y^2

Step-by-step explanation:

-2X² × 4X²y²​ = -8X^4y^2

edit to add:

first: multiply the coefficients together:

-2 x 4 = -8

second: add the exponents of X together (when you multiply exponents, you just add them together):

² & ² = ^4

and you have the answer:

-8X^4y^2

6 0
3 years ago
Read 2 more answers
He sum of three consecutive integers is −369−369. find the three integers.
Alinara [238K]
N + (n+1) + (n+2) = -369
3n + 3 = -369
3n = -366
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4 0
3 years ago
Find the product.
Inga [223]
(2p + 7)(3p-9)
2p x 3p= 6p^2
2p x -9= -18p
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6 0
3 years ago
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Maryland had $(62xsquared + x - 4) on mondays she spent $(11x squared - 33) on a pair of gloves how much money did she have left
Anton [14]

Answer:

$( 51x^2 + x + 29).

Step-by-step explanation:

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=  62x^2 + x - 4 - (11x^2 - 33)   (note we place the amount spent on gloves in parentheses because we have to subtract the whole amount)

Now we distribute the negative over the parentheses:

= 62x^2 + x - 4 - 11x^2 + 33     ( note - 33 becomes -33*-1 = +33)

Now simplifying like terms:

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7 0
3 years ago
Name the sets of numbers to which -7/9 belongs
Arlecino [84]
Ok
the sets are
natural numbers (or counting numbers), this is like 1,2,3,4,5 etc

whole numbers, this is including 0, so 0,1,2,3,4,5,6 etc

integers, this includes the previoius set and negatives, so -3,-2,-1,0,1,2,3,4,5 etc

rational numbers, this is the set of numbers that can be written in form a/b where b≠0, so all integers can be written like this, like example -3=-3/1, so -7/9 belongs here



-7/9 goes in the rational set

5 0
3 years ago
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