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3 years ago

Write a 5 paragraph essay about the Three types of symmetry

Mathematics

2 answers:

Hoochie [10]3 years ago

8 0

B r u h h h h h h h hh h h

adoni [48]3 years ago

5 0

Answer:

ah yes here is some revenge

Step-by-step explanation:

I DONT KNOW:)

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ΔABC has coordinates A(8, −4), B(2, 2), and C(0, −6). Write the coordinates of the image after a dilation with a scale factor of

MakcuM [25]

Answer:

formula= (kx,ky)

where k = scale factor

= A((8,-4)

= A= (8×12,-4×12)

A= (96,-48)

B= (2,2)

= (2×12,2×12)

B= (24,24)

C= (0,-6)

= (0×12,-6×12)

C= (0,-72)

4 0

3 years ago

Graph step by step: f(x)=-2x+1

Paul [167]

Step-by-step explanation:

Root:(1/2, 0)

Domain: x∈R

Range: y∈R

Vertical intercept: (0, 1)

4 0

3 years ago

Which expression is equal to 4 (2+3) ? 1. 2+12 2. 4+5 3. 8+3 4. 8+12

allsm [11]

4. 8+12=20

4 (2+3)
First you add 2+3 and get 5
Next, since the 5 is now in the parentheses, it indicates that you have to multiply
Finally, 5 times 4=20

5 0

3 years ago

Read 2 more answers

A. 15 * (6 + 4) = (15 * ■) + (15 * 4)

jeka57 [31]

Answer:

A)6

B)x 2

C)x

Step-by-step explanation:

3 0

3 years ago

The number of kilograms of water in a human body varies directly as the mass of the body. An 87-kg person contains 58 kg of wat

katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form $y=kx$ , where y varies directly with x and k is constant of variation.

We are told that an 87-kg person contains 58 kg of water. We can represent this information in an equation as:

$58=k\cdot 87$

Let us find the constant of variation as:

$\frac{58}{87}=\frac{k\cdot 87}{87}$

$\frac{29*2}{29*3}=k$

$\frac{2}{3}=k$

The equation $y=\frac{2}{3}x$ represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute $x=75$ in our given equation and solve for y.

$y=\frac{2}{3}(75)$

$y=2(25)$

$y=50$

Therefore, there are 50 kg of water in a 75-kg person.

3 0

3 years ago