Question

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

Answer 1

Answer:

32 units

Step-by-step explanation:

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = $\sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100}$ = 10 units

BC = $\sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16}$ = 4 units

CD = $\sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36}$ = 6 units

AD = $\sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144}$ = 12 units

Perimeter of ABCD = $10+4+6+12$ = 32 units