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BigorU [14]
3 years ago
7

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

Mathematics
1 answer:
dedylja [7]3 years ago
6 0

<u>Answer:</u>

32 units

<u>Step-by-step explanation:</u>

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = \sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100} = 10 units

BC = \sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16} = 4 units

CD = \sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36} = 6 units

AD = \sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144} = 12 units

Perimeter of ABCD = 10+4+6+12 = 32 units

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