Answer:
The author will know where data will be inserted in the document.
Explanation:
A method of taking data from a database, spreadsheet, or other form of structured data, and inserting it into documents such as letters, envelopes and/or mailing labels.
Answer:
Following are the program to this question:
#include <iostream>//defining header file
using namespace std;
void squareOfAsterisks(int x) //defining method squareOfAsterisks
{
int i,j; //defining integer variable
for(i=1;i<=x;i++) //defining loop to print column value
{
for(j=1;j<=x;j++) //defining loop to print row value
{
cout<<"*"; //print value
}
cout<<endl; //for line break
}
}
int main() //defining main method
{
int x; //defining integer variable
cout<<"Enter any number: "; //print message
cin>>x; //input value from user
squareOfAsterisks(x); //calling the method and pass the value
return 0;
}
Output:
Enter any number: 4
****
****
****
****
Explanation:
The description of the above program can be given as follows:
- In the given program a method "squareOfAsterisks" is declared, that accepts an integer value "x" in its arguments, inside the method two integer variable I, j is used, that uses a to print the given pattern.
- In the main method, an integer variable x is declared, which takes input from the user end, and then calls the method, that is "squareOfAsterisks" and passes its value.
<span>An ecommerce application is the software that handles ecommerce transactions. It helps customers to find products, make a selection and submit payment. A key component of an ecommerce application is an online shopping cart. </span>
Hi, you haven't provided the programing language, therefore, we will use python but you can extend it to any programing language by reading the code and the explanation.
Answer:
n1 = int(input("First numeber: "))
n2 = int(input("Second numeber: "))
for i in range(5):
r1 = n1%10
r2 = n2%10
print(r1+r2)
n1 = n1//10
n2 = n2//10
Explanation:
- First, we ask for the user input n1 and n2
- We create a for-loop to calculate the sum of each place-value of two numbers
- We obtain the last number in n1 by using the mod operator (%) an the number ten this way we can always take the last value, we make the same for n2
- Then we print the result of adding the last two numbers (place value)
- Finally, we get rid of the last value and overwrite n1 and n2 to continue with the process
Given an array of integers (both odd and even), sort them in such a way that the first part of the array contains odd numbers sorted in descending order, rest portion contains even numbers sorted in ascending order.
Explanation:
- Partition the input array such that all odd elements are moved to left and all even elements on right. This step takes O(n).
- Once the array is partitioned, sort left and right parts individually. This step takes O(n Log n).
#include <bits/stdc++.h>
using namespace std;
void twoWaySort(int arr[], int n)
{
int l = 0, r = n - 1;
int k = 0;
while (l < r) {
while (arr[l] % 2 != 0) {
l++;
k++;
}
while (arr[r] % 2 == 0 && l < r)
r--;
if (l < r)
swap(arr[l], arr[r]);
}
sort(arr, arr + k, greater<int>());
sort(arr + k, arr + n);
}
int main()
{
int arr[] = { 1, 3, 2, 7, 5, 4 };
int n = sizeof(arr) / sizeof(int);
twoWaySort(arr, n);
for (int i = 0; i < n; i++)
cout << arr[i] << " ";
return 0;
}
