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2 years ago

Tangent is defined as

Mathematics

1 answer:

a_sh-v [17]2 years ago

3 0

Answer:

a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point.

a completely different line of thought or action.

Step-by-step explanation:

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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.

const2013 [10]

Answer:

$T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

Step-by-step explanation:

Remember that for any curve $r(t)$

The tangent vector is given by

$T(t) = \frac{r'(t) }{| r'(t)| }$

And the normal vector is given by

$N(t) = \frac{T'(t)}{|T'(t)|}$

For this case, using the chain rule

$r'(t) = ( -10*2tsin(t^2) , 102t cos(t^2) )\\$

And also remember that

$|r'(t)| = \sqrt{(-10*2tsin(t^2))^2 + ( 10*2t cos(t^2) )^2} \\\\ = \sqrt{400 t^2*( sin(t^2)^2 + cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t$

Therefore

$T(t) = r'(t) / |r'(t) | = ( -10*2tsin(t^2) , 10*2t cos(t^2) )/ 20t\\\\ = ( -10*2tsin(t^2)/ 20t , 10*2t cos(t^2) / 20t )\\= ( -sin(t^2), cos(t^2) )$

Similarly, using the quotient rule and the chain rule

$T'(t) = ( -2t cos(t^2) , -2t sin(t^2))$

And also

$|T'(t)| = \sqrt{ ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t$

Therefore

$N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

Notice that

1. $|N(t)| = |T(t) | = \sqrt{ cos(t^2)^2 + sin(t^2)^2 } = \sqrt{1} = 1$

2. $N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0$

Simlarly

$r'(t) = (2t,-6,0) \\$

and

$|r'(t)| = \sqrt{(2t)^2 + 6^2} = \sqrt{4t^2 + 36}$

Therefore

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

Then

$T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)$

and also

$|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 + ( (3 t)/(9 + t^2)^{3/2})^2 + 0^2 }\\= 3/(t^2 + 9 )$

And since

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

6 0

2 years ago

Do these three segments make a right triangle? 14cm, 23cm, and 25cm

Basile [38]

Answer:

This is not a right triangle(No)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. If there were 45 basket

-BARSIC- [3]

Answer:

B. r + l = 45; 2r + 3l = 96

39 regular; 6 long-distance

Step-by-step explanation:

There were 45 baskets, so

(1) r + l = 45

There were 96 points in the game, so

(2) 2r + 3l = 96

Solve equation (1) for l

l = 45 – r Substitute the value for l in Equation (2)

2r + 3(45 – r) = 96 Remove parentheses

2r + 135 - 3r = 96 Combine like terms

-r + 135 = 96 Subtract 135 from each side

-r = -39 Multiply each side by -1

r = 39 Substitute the value of r in Equation (1)

39 + l = 45 Subtract 39 from each side

l = 6

===============

Check:

(1) 39 + 6 = 45

45 = 45

(2) 2×39 + 3×6 = 96

78 + 18 = 96

96 = 96

4 0

3 years ago

Witch of the following is NOT a characteristic of a plane?

Tanya [424]

Answer:

The answer would be "its width can be measured".

Step-by-step explanation:

8 0

2 years ago

Help pleaseeee!!! i’ll give brainly

Aloiza [94]

1,13
2,26
3,39
4,52
5,65

6 0

2 years ago