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oksian1 [2.3K]
3 years ago
14

*LAST QUESTION, PLEASE HURRY AND ANSWER* What is the volume of the cone below? (Use 3.14 for pi)

Mathematics
1 answer:
enyata [817]3 years ago
4 0

Answer:

<h2>           The third:  5.32 cubic units</h2>

Step-by-step explanation:

R = 1.52

H = 2.2

π = 3.14

V=\frac13\pi R^2\cdot H\\\\V=\frac13\cdot3.14\cdot(1.52)^2\cdot2.2=5.3200810\overline6\approx5.32

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In the distribution, the first quartile,median and mean are 30.8,48.5 and 42.0 respectively. If the co efficient skewness is -0.
finlep [7]

Answer:

The third quartile is 56.45

Step-by-step explanation:

The given parameters are;

The first quartile, Q₁ = 30.8

The median or second quartile, Q₂ = 48.5

The mean, \bar x = 42.0

Coefficient of skewness = -0.38

The Bowley's coefficient of skewness (SK) is given as follows;

SK = \dfrac{Q_3 + Q_1 - 2 \times Q_2}{Q_3 - Q_1}

Plugging in the values, we have;

-0.38 = \dfrac{Q_3 + 30.8 - 2 \times 48.5}{Q_3 - 30.8}

Which gives;

-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5

11.704 - 0.38·Q₃ = Q₃ - 66.2

1.38·Q₃ = 11.704 + 66.2 =  77.904

Q₃ = 56.45

The third quartile = 56.45.

5 0
3 years ago
What is the first step in evaluating the expression below?
Ostrovityanka [42]

Answer:

brackets, then Parenthesis then the FIRST Multiplication then the division and then math and sub and so on a so for

Step-by-step explanation:

6 0
3 years ago
Two less than four times a number is 6
iris [78.8K]

Answer: 2 - 4x = 6

Please mark me as brainliest

5 0
3 years ago
What is the area of a regular hexagon with a side length of 4 m? Enter your answer in the box. Round only your final answer to t
Tanzania [10]
The area of a hexagon is 
A= a^2 (3√3)/2
we replace a with 4
A=41.57
8 0
3 years ago
Read 2 more answers
Solve: <br>x + y = 7<br>3x - 2y = 11<br><br>By using Substituting method.​
Salsk061 [2.6K]

\large\underline{\sf{Solution-}}

\sf  \longmapsto x + y = 7 \: \: - - - (i)

\sf  \longmapsto 3x - 2y = 11 \: \: - - - (ii)

<u>By first equation,</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x = 7 - y

<u>Now, we can find the original value of y.</u>

\sf \longmapsto 3x - 2y = 11

\sf  \longmapsto 3(7 - y) - 2y = 11

\sf  \longmapsto 21 - 3y - 2y = 11

\sf  \longmapsto 21 - 5y = 11

\sf  \longmapsto - 5y = 11 - 21

\sf  \longmapsto - 5y =  - 10

\sf  \longmapsto y = \dfrac{ - 10}{ - 5}

\sf  \longmapsto y = 2

<u>Now, we can find the original value of x.</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x + 2 = 7

\sf  \longmapsto x = 7 - 2

\sf  \longmapsto x = 5

Therefore, the values of x and y are 5 and 2 respectively.

8 0
2 years ago
Read 2 more answers
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