1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natulia [17]
3 years ago
5

In a school gym the ratio of the number of boys to the number of girls were 4:3. After 160 days boys left the gym, the ratio bec

ame 4:5. How many girls were there in the gym?
Mathematics
2 answers:
uysha [10]3 years ago
7 0
 The Answer is 300 girls.   
Allisa [31]3 years ago
4 0
<span>11/29/2017QQuiz 2: Supporting Speeches11/29/2017</span><span>QQuiz 2: Supporting Speeches11/29/2017</span><span>QQuiz 2: Supporting Speeches</span>
You might be interested in
NEED HELP PLEASE SOMEONE!!!!
weqwewe [10]
Let me work this out really quick and I'll get back to you
4 0
3 years ago
How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y
son4ous [18]

Solution:

Given:

x^2=6y

Part A:

The vertex of an up-down facing parabola of the form;

\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}

Rewriting the equation given;

\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\  \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\  \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\  \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\  \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}

Therefore, the focus is;

(0,\frac{3}{2})

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}

Therefore, the directrix is;

y=-\frac{3}{2}

3 0
1 year ago
I need help please with theirs question
crimeas [40]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
The parabola opens upward has x = 2 as an axis of symmetry and contains the non -vertex points (1, 9) and (4, 27) write the equa
Sedaia [141]

Answer:

<h3>               f(x) = 6(x - 2)² + 3</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k    - vertex form of the equation of the parabola with vertex (h, k)

"the parabola opens upward" means:  a>0

"the parabola has x = 2 as an axis of symmetry" means:  h = 2

so f(x) = a(x - 2)² + k

"the parabola contains the point (1, 9)" means:

9 = a(1 - 2)² + k

9 = a(-1)² + k

9 = a + k

k = 9 - a

"the parabola contains the point (4, 27)" means:

27 = a(4 - 2)² + k

so:

27 = a(2)² + 9 - a

27 = 4a + 9 - a

3a = 18

a = 6

and  k = 9 - 6 = 3

Therefore the vertex form for this parabola is:

                                     <u> f(x) = 6(x - 2)² + 3</u>

4 0
3 years ago
I need help figuring out the steps to do this question
krok68 [10]

6x-18                                  14x+38

subtract the 6 from the 6 and the 14 which will give you:                 then add the 18 to the the 18 and the 38  

8x = 56

then divide 8/8 which is zero and 8/56 which equals 7  so ur answer is x=7

3 0
3 years ago
Other questions:
  • What is the solution of log(2t+4) = log(14-3t)?
    8·1 answer
  • Of the birds in Monica's pet shop, 1/5 are pigeons. Of the pigeons, 1/3 are white. Look at each expression. Can it be used to fi
    13·1 answer
  • Write and solve an inequality that represents x. The base is greater than the height. Base: x + 3 in. Height: 8 in.
    15·1 answer
  • Can you write an equivalent fraction for 5/9 and 1/10 using the least common denominator?<br>​
    5·1 answer
  • Please explain btw you can use symbols to use things like √ ² ³
    11·1 answer
  • PLEASEE help I'll mark brainliest. I need to know the
    13·1 answer
  • Which expression is equivalent to 2/3(6x+3)
    11·1 answer
  • A cyclist rides her bike at a rate of 20 kilometers per hour. What is this rate in miles per hour? How many miles will the cycli
    12·1 answer
  • You bought some new fish and need the tank ready. You fill the tank with water and start running the filter system.You check the
    15·1 answer
  • Geometry - Isosceles &amp; Equilateral Tirangles<br><br> Solve for x *
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!