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S_A_V [24]
2 years ago
6

A different class has 254 students, and 58.7% of them are men. How many men are in the class

Mathematics
1 answer:
Vlad [161]2 years ago
6 0

Answer:

432.7 mens ate there in class

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How do you know if a guy likes you especially if he's shy? fre.e points basically
kondor19780726 [428]

Answer:

well it's hard to tell if he's shy, but a small hint to tell would be if he's looking for you a lot in like school or work, or if he's keeping in touch with you, talking to you more than usual, or he gets clingy.

Step-by-step explanation:

6 0
3 years ago
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Find the solution set <br><br>2x^2 -2x -4 =0<br><br>please use a comma to separate your answer.
mariarad [96]

Answer:

2,-1

Step-by-step explanation:

2x^2 -2x -4 =0

Factor out a 2

2(x^2 -x-2) =0

What 2 number multiply to -2 and add to -1

-2*1 = -2

-2 +1 = -1

2(x-2) (x+1) =0

Using the zero product property

x-2 = 0               x+1 = 0

x-2+2=0+2       x+1-1=0-1

x=2                   x=-1

7 0
3 years ago
Assume that 63% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below
mash [69]

Answer:

a. 0.9931

b. 0.3423

c. 0.3907

d. 0.2670

e. 3.15

f. 1.0796

Step-by-step explanation:

The probability of the variable that said the number of left-handed people follow a Binomial distribution, so the probability is:

P(x)=nCx*p^{x}*(1-p)^{n-x}

nCx is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Where x is the number of left-handed people, n is the number of people selected at random and p is the probability that a person is left--handed. So P(x) is:

P(x)=5Cx*0.63^{x}*(1-0.63)^{5-x}

Then the probabilities P(0), P(1), P(2), P(3), P(4) and P(5) are:

P(0)=5C0*0.63^{0}*(1-0.63)^{5-0}=0.0069

P(1)=5C1*0.63^{1}*(1-0.63)^{5-1}=0.0590

P(2)=5C2*0.63^{2}*(1-0.63)^{5-2}=0.2011

P(3)=5C3*0.63^{3}*(1-0.63)^{5-3}=0.3423

P(x)=5C4*0.63^{4}*(1-0.63)^{5-4}=0.2914

P(x)=5C5*0.63^{5}*(1-0.63)^{5-5}=0.0993

Then, the probability P(x≥1) that there are some lefties among the 5 people is:

P(x≥1) = P(1) + P(2) + P(3) + P(4) + P(5)

P(x≥1) = 0.0590 + 0.2011 + 0.3423 + 0.2914 + 0.0993 = 0.9931

The probability P(3) that there are exactly 3 lefties in the group is:

P(3) = 0.3423

The probability P(x≥4) that there are at least 4 lefties in the group is:

P(x≥4) = P(4) + P(5) = 0.2914 + 0.0993 = 0.3907

The probability P(x≤2) that there are no more than 2 lefties in the group is:

P(x≤2) = P(0) + P(1) + P(2) = 0.0069 + 0.0590 + 0.2011 = 0.2670

On the other hand, the expected value E(x) and standard deviation S(x) of the variable that follows a binomial distribution is:

E(x)=np=5(0.63)=3.15\\S(x)=\sqrt{np(1-p)}=\sqrt{5(0.63)(1-0.63)}=1.0796

6 0
3 years ago
Write the algebraic rule for transforming a figure by moving it 4 units to the left and 5 units up
dezoksy [38]

Answer:

Translation: 5 units right and 2 units up

Step-by-step explanation:

7 0
3 years ago
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Which of the following best explains why President Nixon referred to
slamgirl [31]
The answer is B on edge
3 0
2 years ago
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