Given f(x)= 3x+21. A. F(4)=B. F(X)= 50, X=2. C. F(-5)=D. F(X)= -34, X=

Mathematics

1 answer:

nignag [31]2 years ago

4 0

The given function is

$f(x)=3x+2$

A . f(4) means we have to evaluate the function when x = 4.

$f(4)=3(4)+2=12+2=14$ <h2>Therefore, f(4) = 14.</h2>

B. f(x) = 50 means we have to evaluate the function when y = 50.-

$\begin{gathered} 50=3x+2 \\ 50-2=3x \\ x=\frac{48}{3} \\ x=16 \end{gathered}$ <h2>Therefore, f(16) = 50.</h2>

C. f(-5) means we have to evaluate the function when x = -5.

$f(-5)=3(-5)+2=-15+2=-13$ <h2>Therefore, f(-5) = -13.</h2>

D. f(x) = -34.

$\begin{gathered} -34=3x+2 \\ -34-2=3x \\ x=\frac{-36}{3} \\ x=-12 \end{gathered}$ <h2>Therefore f(-12) = -34.</h2>

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HELP ASAP!!!!!!!!!!

chubhunter [2.5K]

Answer:

7.5

Step-by-step explanation:

$\sqrt{0\\.3}$ = 0.5477225575

Multiply it by 5

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Square it

7.5 $ft^{2}$

Hope this helped. :)

5 0

3 years ago

Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th

sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

$P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}$

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

$P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%$