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2 years ago

How do i work this problem y= -3x - 5

1 answer:

7 0

This is a linear function. you can list out a group of domains or x, then you will get outcomes, which will be your range

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

2 years ago

-y (2 - 5y + 4)<br> Simplify plz

Neko [114]

This equation simplified would be

-y(-5y+6)

3 0

2 years ago

Read 2 more answers

Help me please? :( (;´༎ຶД༎ຶ`)(;´༎ຶД༎ຶ`)(;´༎ຶД༎ຶ`)

Gnesinka [82]

Answer:

a) 22:53

b)213 min

Step-by-step explanation:

c) 10 17 + 4 = 14 17

she has 2 minutes to spare

5 0

2 years ago

A mistake was made in the steps shown to simplify the expression. Which step includes the mistake?

kolezko [41]

Step 2 how did the 8 get there?

6 0

2 years ago

The table shows the amount of money in Shawn's bank account as a

fredd [130]

Answer:

400000000 dollar

Step-by-step explanation:

because why not

5 0

1 year ago