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jasenka [17]
3 years ago
5

Whats 1+1 ?????????? PLEASE IM DUMB

Mathematics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

Step-by-step explanation:

2

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I think the answer is 12
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Give an example of a real-life continuous function.
prisoha [69]

Answer:

Math is a continuous function. It can keep going on and on.

Step-by-step explanation:

Hope I <em><u>Helped!</u></em> :D

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Billy ate 1/3 of a bag of sunflower seeds each day for 5days.How many bags of sunflower seeds did he eat ?
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3 years ago
Read 2 more answers
Fully Factor 3x^2 – 16x + 20
ryzh [129]

Answer:

C. (3x2 - 10) (x - 2)

Step-by-step explanation:

3x^2 - 16x +20

Step 1: Sum = - 16x

Product = 60x^2

Step 2: Find 2 numbers that their sum is -16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and -6

Step 3: Replace -16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20

Step 4: Factorise the equation in step 3, like so;

(3x^2 - 6x)(- 10x + 20)

3x(x - 2) -10(x - 2)

(3x - 10)(x - 2)

To check if the answer is correct, expand the bracket: (3x - 10)(x - 2)

If the bracket is opened properly, you will get 3x^2 - 16x + 20

4 0
3 years ago
A cup of coffee has approximately 310 mg of caffeine. Each hour, the caffeine in your system decreases by about 35%. How much ca
Alex787 [66]

Answer:

∴35.97 mg caffeine would be left in the system after 5 hours.

Step-by-step explanation:

Given that,

A cup of coffee has approximately 310 mg of caffeine.

Caffeine decrease at a rate 35% per hour.

Exponential Function:

y(t)=y_0(1-r)^t

y(t)= Amount caffeine after t hours

y_0= Initial amount of caffeine

r= rate of decrease

t = Time in hour.

Here y(t)=?, y_0 = 310 mg, r=35%=0.35, t= 5 hours

y(t)=310(1-0.35)^5

      =35.97 mg

∴35.97 mg caffeine would be left in the system after 5 hours.

3 0
3 years ago
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