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3 years ago

7

What is the property when u multiply numerator and then multiply denominator and simplify

1 answer:

Alona [7]3 years ago

8 0

<span>A new notationWe will start using a new way to indicate simplifying fractions. When a numerator or
a denominator gets simplified, we will cross it out with a slash and write the new
numerator or denominator next to it (either above it or below it).The number you divide by (the 4) does not get indicated in any way! You only
think about it in your mind: “I divide 12 by 4, and get 3. I divide 20 by 4, and get 5.”You may not see any advantage over the “old” method yet, but this shortcut will
come in handy soon.</span>

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Simplify (4−b)(5b2+5b−4)

astraxan [27]

Answer:15b^2-5b^3+24b-16

Step-by-step explanation:

(4-b)(5b^2+5b-4)

Open the brackets

20b^2+20b-16-5b^3-5b^2+4b

Collect like terms

20b^2-5b^2-5b^3+20b+4b-16

15b^2-5b^3+24b-16

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3 years ago

How to figure out 2.73+0.003+0.158

Zinaida [17]

Fun!

Line Up the decimals like a vertical addition problem.

Answer: 2.89100

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3 years ago

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Mei runs 91.08 miles in 3 weeks. If she runs 6 days each week, what is the average distance she runs each day?

egoroff_w [7]

5.06 miles per day

Calculate the amount of days, so 6 x 3 = 18
Then, divide that by 91.08

4 0

3 years ago

Jackie had $135 to spend at the mall. She spent 29% of that money on a dress. Jackie spent $___ on the dress. (Make sure to ente

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

100-29= 71

0.71 x $135=$95.85

$135 - $95.85= $39.15

$39.15 left, she spent $95.85

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3 years ago

The top and bottom margins of a poster are each $3$ cm and the side margins are each $2$ cm. If the area of printed material on

babymother [125]

Answer:

Therefore the dimension of the poster is 12 cm by 8 cm.

Step-by-step explanation:

Let the length of the poster be x and the width be y.

Given that the area of the poster is 96 cm².

∴xy =96

$\Rightarrow y= \frac{96}{x}$

The sides margins each are 2 cm and the top and bottom margins of the poster are each 3 cm.

The length of printing space is =(x- 2.3) cm

= (x-6) cm

The width of the printing space is =(y-2.2) cm

=( y-4 )cm

The area of the printing space is A=(x-6)(y-4) cm²

∴A=(x-6)(y-4)

$\Rightarrow A=(x-6)(\frac{96}{x}-4)$ [ Putting $y= \frac{96}{x}$ ]

$\Rightarrow A=120-\frac{576}{x}-4x$

Differentiating with respect to x

$A'= \frac{576}{x^2}-4$

Again differentiating with respect to x

$A''=-\frac{1152}{x^3}$

To find the minimum area, we set A'=0

$\therefore \frac{576}{x^2}-4=0$

$\Rightarrow \frac{576}{x^2}=4$

$\Rightarrow x^2=\frac{576}{4}$

$\Rightarrow x^2 =144$

$\Rightarrow x=\pm 12$

Dimension can't be negative.

Therefore x=12

If x=12, the value of A''>0,then at x=12, the area of the poster will be minimum.

If x=12, the value of A''<0,then at x=12, the area of the poster will be minimum.

$\therefore A''|_{x=12}=-\frac{1152}{12^3}$

Therefore at x= 12 cm the area of the poster will be maximum.

The width of the poster is $y=\frac{96}{12}$ = 8 cm

Therefore the dimension of the poster is 12 cm by 8 cm.

3 0

3 years ago