Answer:
The correct answer is - 1/2 or 50% for first and second child to be affected.
Step-by-step explanation:
Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.
A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.
a cross between affected or dwarf and normal parent
Aa X aa
Punnett square:
a a
A Aa Aa
a aa aa
Aa- dwarfness
aa- normal height
The probability that both their first child and second child would have achondroplasia is
2/4 =1/2 or 50%.
Answer: -16
Step-by-step explanation:
-12-4=-16
Making -16+4=-12
Answer:
g = 4.6
Step-by-step explanation:
-3(g - 3) = 2(g - 7)
-3g + 9 = 2g - 14
-3g = 2g - 23
-5g = -23
g = 4.6
Hello!
The range is the lowest number subtracted from the highest number
The lowest number is 1
The highest number is 9
9 - 1 = 8
The range is 8
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To find the median you look at the line that separates the box plot into two sections
The median is 4
Hope this helps!
4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0
where y' = dy/dx
8x + 5xy' +5y -2yy' = 0
combining y' terms
y' (5x-2y) +8x +5y = 0
y'(5x-2y) = -(8x+5y)
dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)