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faltersainse [42]

2 years ago

5

a figure has been dilated by a scale factor of 2. which transformation could be used to prove the figures are similar using the

AA similarity postulate ?

1 answer:

mash [69]2 years ago

4 0

Answer:

translation maybe

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Find the x- and y-intercepts of the graph of the linear equation −4x+8y=−16.

Bogdan [553]

Put it in slope form: y=mx+b
8y= 4x-16
Divide by 8
Y = 1/2x -2
1/2 is x intercept and -2 is y intercept

8 0

2 years ago

Fiona was thinking of a number. Fiona doubles it and adds 5.1 to get an answer of 11.5. Form an equation with x? Whats the answe

saveliy_v [14]

Answer:

3.2

Step-by-step explanation:

11.5 - 5.1 = 6.4

6.4 ÷ 2 = 3.2

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2 years ago

The angles of a quadrilateral all have the same measure. What is the name of the quadrilateral?

castortr0y [4]

The quadrilateral is either a square or a rectangle as all angles are the same measure (90 degrees)

8 0

2 years ago

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Simplify (2n + 5) - (3n + 7) + (4n - 9).<br> -3n - 11<br> 3n - 11<br> -3n + 11<br> 3n + 11

Natasha2012 [34]

Answer:

(B) 3n - 11

Step-by-step explanation:

(2n + 5) - (3n + 7) + (4n - 9) = 2n + 5 - 3n - 7 +4n - 9 = 3n - 11

3 0

2 years ago

If the shaded cross sections of the solids have the same area, which of the following corresponds to the value of a: the side le

Nikolay [14]

Answer:

$4\sqrt{\pi}$

Step-by-step explanation:

The cross section of a sphere is a circle with area $\pi r^2$ , where radius is given as 4
The cross section of the cube is a square with area $a^2$ , where a is side length of square

The circle area = the square area. Thus we have:

$\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}$

6 0

2 years ago

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