All categories

3 years ago

A vehicle weighs 18,00 pounds how many tons the the vehicle weigh

Mathematics

2 answers:

lara [203]3 years ago

7 0

Hi there! I'm glad I was able to help you!

Assuming you meant 1,800, our vehicle technically weighs one FULL ton. However, if you were to round to the nearest thousandth, it would be about two tons.

A ton is equivalent 1,000 pounds, therefore with a vehicle weighing around 1,800 pounds, its weight is rounded to two tons, but if you want to get even more technical it's 1 full ton and 4/5ths, or 1.8!

I hope this sort of helped you to understand the question & answer a little bit better! :)

Lady bird [3.3K]3 years ago

4 0

Answer:

0.9 tons or 9 tons

Step-by-step explanation:

<u>For 1800 pounds</u>

1 ton = 0.0005 pounds

0.9 tons = 1800 pounds

<u>For 18000 pounds</u>

1 ton = 0.0005 pounds

9 tons = 18000 pounds

You might be interested in

If f(x)=x-5 and g(x)=3x+11, find (f+g)(x).

lawyer [7]

Answer:

4x+6

Step-by-step explanation:

x-5+(3x+11)=4x+6

4 0

3 years ago

Compare using <, >, = 5+(-4)____-4 + (-7)

nikitadnepr [17]

Good morning,

Answer:

Step-by-step explanation:

5+(-4) = 5 - 4 = 1

-4 + (-7) = -(4+7) = -11

since 1 > -11 then 5+(-4) > -4 + (-7)

4 0

3 years ago

There are four blue marbles, an unknown number of red (r) marbles, and six yellow marbles in a bag. Which expression represents

MAXImum [283]

Answer:

There are a total of 4 + r + 6 marbles in the bag

The probability of a blue is $\frac{4}{10+r}$

The probability of a red is $\frac{r}{10+r}$

The probability of choosing a blue, replacing it and then a red is

$\frac{4}{10+r}$ × $\frac{r}{10+r}$ = [tex]\frac{4r}{100+20r+ r^{2} /[tex]

Step-by-step explanation:

6 0

3 years ago

What can you say about his average speed?

Nikitich [7]

The answer should be E. 223- 6s = 0

5 0

3 years ago

The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x

RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

P(a < X < b) = $\int_{a}^{b} \frac{2}{x^{3}} dx$ = $2\int_{a}^{b} x^{-3} dx$

= $2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx$ { Because $\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a$ }

= $2[ \frac{x^{-2} }{-2}]^{b}_a$ = $\frac{2}{-2} [ x^{-2} ]^{b}_a$

= $-1 [ b^{-2} - a^{-2} ]$ = $\frac{1}{a^{2} } - \frac{1}{b^{2} }$

a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }

Comparing with general probability we get,

P(1 < X < 5) = $\frac{1}{1^{2} } - \frac{1}{5^{2} }$ = $1 - \frac{1}{25}$ = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/ $8^{2}$ - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = $\frac{1}{6^{2} } - \frac{1}{10^{2} }$ = $\frac{1}{36} - \frac{1}{100 }$ = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

= $(\frac{1}{1^{2} } - \frac{1}{6^{2} })$ + (1/ $10^{2}$ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

⇒ P(1 < X < x) = 0.75

⇒ $\frac{1}{1^{2} } - \frac{1}{x^{2} }$ = 0.75

⇒ $\frac{1} {x^{2} }$ = 1 - 0.75 = 0.25

⇒ $x^{2}$ = $\frac{1}{0.25}$ ⇒ $x^{2}$ = 4 ⇒ x = $2$

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0

3 years ago