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Serggg [28]
3 years ago
11

Which is bigger? 2^4 or 4^2?​

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

Both are equal

Step-by-step explanation:

2^4 = 16 \\  \\  {4}^{2}  = 16 \\  \\ \implies \:  {2}^{4}  =  {4}^{2}

AlexFokin [52]3 years ago
6 0

Answer:

Step-by-step explanation:

2^4=16 and 4^2=16

They both equal the same thing so im guessing neither. They are both the same value.

Hope this helped!

PLS let me know if i'm wrong so i can correct my mistake!!

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To determine the number of trout in a lake, a conservationist catches 132 trout, tags them and throws them back
andrey2020 [161]

Answer:

boo

Step-by-step explanation:

6 0
3 years ago
Eight more than the product of four and a number is twice the sum of the number and six. Write an equation that can be used to s
masha68 [24]
4n+8=2(n+6)
Now isolate the n on one side of the equation:
4n+8=2n+12(distribution of the 2)
4n=2n+4(combine like terms)
2n=4(combine like variables)
N=2(isolate the n)

The answer is 2
Good luck!
3 0
3 years ago
PLEASE I NEED MAJOR HELP (PICTURE IS DOWN BELOW)
rusak2 [61]
26. 

You simply read the table on this one
3 0
3 years ago
Read 2 more answers
Help me pleaseeeeeeeee
Mashutka [201]

Answer:

The answer is 7

Step-by-step explanation:

25 times 25=625

24 time 24=576

625-576=7

And the square root of 49 is 7.

4 0
2 years ago
Read 2 more answers
The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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