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H (x) = 5x^2+40x+64
y = (5x^2+40x+60) + 4
y = 5(x^2+8x+12) + 4
y = 5(x+2)(x+6) + 4
y-4 = 5(x+2)(x+6)
This means that the solutions, or where the parabola crosses the x-axis, are at x+2=0 and x+6=0, or x=-2, -6
So the midpoint of -2 and -6 is -4, the axis of symmetry is x=-4
Answer:
sinθ = 5/13
cosθ = 12/13
tanθ = 5/12
Step-by-step explanation:
Get the remaining side(hypotenuse) first,
hypotenuse^2 = 12^2 + 5^2 (Pyth. theorem)
hypotenuse = 13
sinθ = 5/13
cosθ = 12/13
tanθ = 5/12
Answer:
The value of x is 6
Step-by-step explanation:
we know that
If two angles are supplementary, then their sum is equal to 180 degrees
so
In this problem
m∠C+m∠E=180°
we have
m∠C=112°
m∠E=(3x+50)°
substitute and solve for x
112°+(3x+50)°=180°
3x+162=180
3x=180-162
3x=18
x=6
The Pythagorean theorem tells you that distance is
.. √((-24)^2 +32^2)) = √(576 +1024) = √1600 = 40
