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mariarad [96]
4 years ago
10

Write the half-reaction for ribose conversion to CO2. Is it an oxidation- or reduction- half reaction

Chemistry
1 answer:
Fittoniya [83]4 years ago
3 0

Answer:

5H_2O+C_5H_{10}O_5\rightarrow 5CO_2+20H^++20e^-

Explanation:

Hello.

In this case, when ribose (C₅H₁₀O₅) yields carbon dioxide (CO₂) we write:

C_5H_{10}O_5\rightarrow CO_2

Which needs to be balanced by adding water and hydrogen ions:

5H_2O+C_5H_{10}O_5\rightarrow 5CO_2+20H^++20e^-

You can also see that there are 20 transferred electrons, since the carbon atoms in the ribose have 0 as their oxidation state and the carbon atoms in the carbon dioxide have +4 as the oxidation state, thus, each carbon transfers  4 electrons, a five carbon atoms transfer 20 electrons overall.

In such a way, since the carbon is increasing its oxidation state, such half reaction is an oxidation half reaction.

Best regards.

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Answer:

Group 1

Explanation:

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Answer:

0.305 mol

Explanation:

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A student carried out a titration using HC2H3O2(aq) and NaOH(aq). The net ionic equation for the neutralization reaction that oc
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Answer:

The  ratio of HC2H3O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) to HC2H3O2(aq) in the flask after the addition of 1.0mL of NaOH(aq) is 15 : 19 .

Explanation:

HC2H3O2 is  CH₃⁻ COOH, which is also known as Acetic acid.

IUPAC name of this compound is Ethanoic acid.

Acetic acid has a basicity of 1. so there is one acidic hydrogen is acetic acid.

Given that, equivalence point was reached when 20.0mL of NaOH is added.

let the normality of acetic acid is N₁ and that of NaOH is N₂.

    volume of acetic acid is V₁ and that of NaOH is V₂.  

 Equivalence point occurs when, N₁ × V₁ =  N₂ × V₂.

⇒  N₁ × V₁ =  N₂ × 20.

after the addition of 5.0mL of NaOH(aq), remaining N₁ × V°  = N₂ × (20 - 5).

                                                                                                  = N₂ × 15.

after the addition of 1.0mL of NaOH(aq), remaining N₁ × Vˣ = N₂ × (20 - 1).

                                                                                                  = N₂ × 19.

⇒ V° : Vˣ = 15 : 19 .

⇒

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