The equilibrium constant expression for this reaction that takes place in water and involve ions can be written as K= [H_3 O^+ ][OH^- ]/([H_2 O] ^2 ). But the concentration of undissociated water, H_2 O is much larger than the concentration of the ions that is essentially remains constant. Therefore, we can include it in the equilibrium constant. The resulting new equilibrium constant can be written: K_W= [H_3 O^+ ][OH^- ].
Answer:
Gaseous at standard conditions.
Explanation:
Hello,
In this case, for the given normal boiling point of oxygen, we can notice those are conditions far away from the standard conditions which are 25 °C. In such a way, since the standard temperature is by far higher than the normal boiling point, the most likely state of a sample of pure oxygen would be gaseous since the molecules will move based on the kinetic theory of gases due to the relatively high temperature which make them be separated and moving all around.
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Answer:
different ways to pollute the air
Explanation:
just think of it like this what is black smoke to nothing lol the black smoke goes up into the atmosphere and pollutes the air just as somebody throwing trash into the ocean and polluting the ocean
35.453
used a science book for the answer
Answer: Exergonic reactions
Explanation: From the research I did, exergonic reactions occur spontaneously because they don't need the addition of energy to occur.
I hope this helps!
