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3 years ago

A company sells artwork using a website. Information about the number of people that

Mathematics

2 answers:

labwork [276]3 years ago

8 0

Answer:c

Step-by-step explanation:

VARVARA [1.3K]3 years ago

6 0

The probability that the next person that visits the website will purchase more than 1 piece of artwork is $\frac{3}{50}$ .

Step-by-step explanation:

Step 1; The probability of an event is given by dividing the number of favorable outcomes i.e. the number of people that brought more than one piece of artwork by the total number of outcomes i.e. the total number of people that visited the website.

Step 2; The probability is calculated by the following values;

The number of favorable outcomes = the number of people that purchased more than one piece of artwork = 9

The total number of outcomes = The number of people that did not buy any artwork + the number of people that brought one piece of artwork + the number of people that brought more than one piece of artwork

= 117 + 24 + 9 = 150.

The probability that the next person that visits the website will purchase more than 1 piece of artwork = $\frac{9}{150}$ = $\frac{3}{50}$ .

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Mark bought three pairs of shorts and one pair of shoes. If the shoes cost $25 and he spent

Aleonysh [2.5K]

Answer:

17.95 :)

Step-by-step explanation:

25-78.85= 53.85, and 53.85/3= 17.95 so each pair of shorts costed 17.95

8 0

2 years ago

Question 6 (1.25 points)

Lisa [10]

Answer:

Test statistic Z= 1.713

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

Step-by-step explanation:

Step(i):-

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

H₀: x⁻ = μ

Alternative Hypothesis : x⁻ ≠ μ

Step(ii):-

Test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }$

Z = 1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

4 0

3 years ago

As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim

AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0

2 years ago

what is c to the negative 3 power and d to the 5 power over f to the 3 power and g to the negative 7 power

julia-pushkina [17]

Answer:

C^-3+d^5/f^3+g^-7

Step-by-step explanation:

The answer is as seen above

8 0

2 years ago

There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the

Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = 14.13.12! = 14.13 = 91

12! 2! 2

C₁₆,₂ = 16.15.14! = 16.15 = 120

14! 2! 2

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = 14.13.12.11.10! = 14.13.12.11 = 1001

10! 4! 4.3.2.1

C₁₆,₄ = 16.15.14.13.12! = 16.15.14.13 = 1820

12! 4! 4.3.2.1

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

7 0

3 years ago