Answer:
B - 2 hours
Step-by-step explanation:
find the rate for each scenario until you find one that matches.
for A 1 hour:
Ben charges (15.50×1hour) = 15.50
Cathie charges (9.25 × 1 hour) + 12.50 flat fee = 21.75
<u>THESE</u><u> </u><u>DO</u><u> </u><u>NOT</u><u> </u><u>MATCH</u>
so you do B 2 hours:
Ben charges 15.50× 2hours = 31
Cathie charges (9.25 × 2hours) + 12.50 flat fee = 31
<em><u>THESE</u></em><em><u> </u></em><em><u>MATCH</u></em><em><u> </u></em><em><u>SO</u></em><em><u> </u></em><em><u>THIS</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>ANSWER</u></em>
If you continue like this for 3 hours and 4 hours the values don't match. <em><u>so the only answer is B</u></em><em><u>.</u></em>
Answer:
-1
Step-by-step explanation:
Put -2 3/4 into an improper fraction -6/4
Then put it into a decimal -1.5
Then put 1/2 into a decimal 1.5
Then divide -1.5 by 1.5
You would get -1
Answer:
48
Step-by-step explanation:
let s be the snowman, g be the girl, and t be the christmas tree
2s+g=24
2t+2ts=132
3t+2g=26
subtract 2 times the first equation from the third one to get
3t-4s=-22
from the second equation we can deduce
2t(1+s)=132
t(1+s)=66
t=66/(1+s)
Substitute:
3(66)/(1+s)-4s=-22
3(66)/(1+s)=4s-22
3(66)=(4s-22)(1+s)
3(66)=-18s+4s^2-22
4s^2-18s-220=0
using the quadratic formula, we get s = 10, s = -5.5.
2(10)+g=24
g=4
2t(1+10)=132
2t=12
t=6
So 2s+t*g= 20+6*4=48
you would get a different solution for the negative s, but since snowmen cannot be negative, 48 is the answe.r
Answer:
Calculate the skid speed by multiplying the drag factor times the braking efficiency times the skid distance times 30 and taking the square root of the result. For example, if the car skidded 120.5 feet on a road with a drag factor of 0.5 and left four skid marks, the car was going about 42.51 mph.
Step-by-step explanation:
Answer:
2/3
Step-by-step explanation:
that the ratio of that number
