Answer:
(C) f
Explanation:
For a simple harmonic oscillator in the form of a loaded spring, its frequency is given by
where <em>k</em> is the spring constant and <em>m</em> is the mass of the load.
It is observed that the amplitude of the spring does not factor into this equation. Hence, the frequency is independent of the amplitude and remains the same.
The same applies to a simple pendulum whose frequency is given by
<em>l</em> is the length of the pendulum and <em>g</em> is the acceleration of gravity.
It is observed as well that the amplitude does not appear in the equation.
kinematic equations... vertical motion, with a=g=10 ...9500=1/2at^2 ...9500=1/2x10xt^2 ... t=root 1900 ...horizontal motion ...speed=dist/time = 808/root1900 ... calculator ...
Answer:
Approximately along the slope, assuming that no energy was lost to friction.
Explanation:
Let denote the initial velocity of this vehicle. Let denote the mass of this vehicle. The kinetic energy (KE) of this vehicle would have initially been:
.
The gain in the gravitational potential energy (GPE) of this vehicle is proportional to the increase in its height.
Let denote the gravitational field strength. on the earth. If the increase in the height of this vehicle is , this vehicle would have gained GPE:
.
Hence, the height of this vehicle is maximal when the GPE of this vehicle is maximized.
Since the vehicle went out of fuel, all its GPE would have been converted from KE. Assuming that no energy was converted to friction. The GPE of this vehicle would be maximal when the entirety of the KE was converted to GPE.
Hence, the maximal GPE of this vehicle would be equal to its initial KE:
.
The maximum height of this vehicle would be:
.
Given that , the maximum height of this vehicle would be:
.
Refer to the diagram attached. The distance that this vehicle traveled along the slope would be approximately:
.
B Light waves travel faster than sound waves
Hello!!
For calculate the Velocity of the wave let's applicate the formula:
V = Velocity = ?
f = Frequency = 300 Hz
= Wavelength = 1,1 m
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