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ipn [44]
3 years ago
13

If a Mack truck and Honda Civic have a headon collision, upon which vehicle is the impact force greater and which vehicle experi

ences the greater acceleration? 1. The forces are the same; the truck experiences the greater acceleration. 2. The force on the truck is greater; the accelerations are the same. 3. All are wrong. 4. The forces are the same; the Civic experiences the greater acceleration. 5. The forces are the same; the accelerations are same.
Physics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

The answer would be 3

Explanation:

This is because a civic would have the greater acceleration and the impact force would be higher for the civic.

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4 0
3 years ago
A long hollow cylindrical conductor (inner radius = 2.0 mm, outer radius = 4.0 mm) carries a current of 12 a distributed uniform
11Alexandr11 [23.1K]

Here we can use ampere'a law to find the magnetic field

\int B.dl = \mu_o i_{en}

B*2 \pi r = \mu_o (i_1 + \frac{i_2*\pi(3^2 - 2^2)}{\pi(4^2 - 2^2}

B*2 \pi*0.003 = 4\pi * 10^{-7} (12 + 5)

B = 4\pi * 10^{-7} (12 + 5)

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3 0
3 years ago
While John is traveling along a straight interstate highway, he notices that the mile marker reads 249 km. John travels until he
erastova [34]

Answer:

Explanation:

Displacement can be displayed as a vector, this because it has magnitud and direction. Because of this, we can think John's Resultant Displacement as the join of this two vectors.

The First Vector is from the 249 Km Marker to the 141 Km Marker, which give us a Vector with a Magnitude equals to 108 Km.

The Second Vector goes from 141 Km Marker to the 174 Km Marker, which give us a Vector with a Magnitude equals to 33 Km.

However is important to know the direction for each Vector, we notice that John was traveling on one direction and then he returned. This makes our Vector to have a different direction, and this means difference signs. Difference signs means substraction. So, the Third Vector will be:

Third Vector = 108 Km - 33 Km

Third Vector = 75 Km

8 0
4 years ago
A snowball starting at rest rolls down a hill and reaches 5 m/s. If the hill is
Lostsunrise [7]

Answer:

The acceleration of the snowball is 0.3125

Explanation:

The initial speed of the snowball up the hill, u = 0

The speed the snowball reaches, v = 5 m/s

The length of the hill, s = 40 m

The equation of motion of the snowball given the above parameters is therefore;

v² = u² + 2·a·s

Where;

a = The acceleration of the snowball

Plugging in the values, we have;

5² = 0² + 2 × a × 40

∴ 2 ×  40 × a  = 5² = 25

80 × a = 25

a = 25/80 = 5/16

a = The acceleration of the snowball = 5/16 m/s².

The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .

4 0
3 years ago
A truck is moving at 2.0 m/s accelerates at a rate of +2.00 m/s2. It does this over a distance of 400.0m. Find the final velocit
otez555 [7]

If <em>v</em> is the truck's final velocity, then

<em>v</em>² - (2.0 m/s)² = 2 * (2.00 m/s²) * (400.0 m)

<em>v</em>² = 1604 m²/s²

<em>v</em> = 40.05 m/s ≈ 40 m/s

3 0
3 years ago
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