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VLD [36.1K]
3 years ago
9

Which of the following statements accurately describes the sign of the work done on the box by the force of the push?

Physics
1 answer:
USPshnik [31]3 years ago
4 0

Answer: positive

Explanation: according to newton's second law of motion, the applied force (pull) will produce a motion for the box defined by the formulae

f = ma, where m is the mass of the box and a is the acceleration.

But due to friction, a force of the same magnitude but opposite in direction to the push is applied, hence we have that

f - fr = ma

Where fr is the frictional force.

As we can see from the formulae, f (push) is responsible for a positive work while fr (friction) will bring about a negative work done.

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The change in momentum of an object is equal to the ____________ that acts on it.
meriva

Answer : The change in momentum of an object is equal to the impulse that acts on it.

Explanation :

Change in momentum : The change in momentum of an object is the product of the mass and the change in velocity of an object.

The formula of change in momentum is,

\Delta p=m\times \Delta v

Impulse : An impulse of an object is the product of the force applied on an object and the change in time. Impulse is also equivalent to the change in momentum of  an object.

J=F\times \Delta t

Proof :

J=F\times \Delta t\\\\J=(m\times a)\times \Delta t\\\\J=m\times (a\times \Delta t)\\\\J=m\times \Delta v=\Delta p

Hence, the change in momentum of an object is equal to the impulse that acts on it.

3 0
3 years ago
Read 2 more answers
the electron are accelrated to a speed of 2.40*10^7 in 1.8*10^-9, the force experinced by an electron ?
dalvyx [7]
Force = mass × acceleration

To find acceleration, we can divide the speed by the time it took:

acceleration = 2.40×10^7 / 1.8×10^-9

acceleration = 1.33×10^16

the mass is equal to the mass of an electron

force = (9.11×10^-31)(1.33×10^16)

force = 1.21×10^-14 N
3 0
3 years ago
PLZ HELP ITS A TIMED TEST!!!!!!!!!!!!!!!!
sergij07 [2.7K]
Image #3 good luck!!!!!!!!!!!
7 0
3 years ago
A projectile is launched vertically at 100 m/s. If air resistance can be ignored, at what speed will it return to its initial le
eduard
<h2>Speed with which it return to its initial level is 100 m/s</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 100 m/s  

Acceleration, a = -9.81 m/s²  

Final velocity, v = ?

Displacement, s = 0 m  

Substituting  

v² = u² + 2as

v² = 100² + 2 x -9.81 x 0

v² = 100²

v = ±100 m/s

+100 m/s is initial velocity and -100 m/s is final velocity.

Speed with which it return to its initial level is 100 m/s

7 0
2 years ago
Read 2 more answers
An airplane has an effective wing surface area of 19.4 m2 that is generating the lift force. In level flight the air speed over
alexgriva [62]

Answer:

W =23807.68 N

Explanation:

given,

surface area of wing = 19.4 m²

speed over top wing = 67 m/s

speed under wing = 51 m/s

density of air =  1.3 kg/m³

weight of plane

From Bernoulli's principle

P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho_2^2

where 1 and 2 are two different locations at the same geo potential level  

so if we call 1 the lower surface and 2 the upper surface,

we find the pressure differential, P₁ -P₂

\Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

\Delta P =\dfrac{1}{2}\times 1.3 \times (67^2-51^2)

\Delta P =1227.2\ N/m^2

then the force acting on the plane is

F=P A

F=1227.2 x 19.4

F =23807.68 N

weight of the plane

W =23807.68 N

7 0
3 years ago
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