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natka813 [3]
3 years ago
11

Sarah heated two cubes of aluminum to 50°C. Cube A has a volume of four cubic centimeters. Cube B has a volume of two cubic cent

imeters. If the cubes do not touch each other, which of these statements is true?
Cube A has a higher temperature than cube B.

Cube B has a higher temperature than cube A.

Cube A has more thermal energy than cube B.

Cube B has more thermal energy than cube A.

electrical energy

electromagnetic energy
Physics
2 answers:
dalvyx [7]3 years ago
6 0

Cube A has more thermal energy than cube B.

Explanation:

It is obvious that cube A has gained more thermal energy compared to cube B.

From the description of the experiment, both cubes had the same temperature which is 50°C. Temperature is the degree of hotness or coldness of a body.

Thermal energy is a form of energy expressed as heat in a body.

Cube A has a higher volume because it has gained more thermal energy than Cube B.

Thermal energy increases the rate of vibration of atoms in the crystal lattice of the solid. The more the thermal energy, the more the vibration. This is  why Cube A has expanded so much and changed volume.

Learn more:

Temperature and heat brainly.com/question/914750

#learnwithBrainly

balandron [24]3 years ago
4 0

Answer:

Cube B has more thermal energy than cube A.

Explanation:

Thermal energy is the measure of the average kinetic energy of the molecules of a matter, which is also inversely proportional to the mass. Since cube B has lesser mass, then fewer molecules. Thus it would have more thermal energy than that of cube A.

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A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrat
Masteriza [31]

Answer:

F2 = 834 N

Explanation:

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²

Where r1 = (d1)/2 = 0.63/2

r1 = 0.315 m

Thus, I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

I•α = F1•r1 - F2•r2

Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

Thus;

0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)

>> 0.76384 = 38.115 - (0.0448F2)

>> 0.0448F2 = 38.115 - 0.76384

>> F2 = (38.115 - 0.76384)/0.0448

>> F2 = 833.73 N

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