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dlinn [17]
3 years ago
5

Physics friction Homework

Physics
1 answer:
zavuch27 [327]3 years ago
6 0
There will be 4 forces on the phone in total. 
1. gravity
2. normal force from the windshield
3. dynamic friction
4. a push from the car

The sum of all 4 forces must achieve an acceleration of 23,6 cm/s² or a total force of F = m * a = 0.1774kg * 0.236m/s² = 0.0419N.

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15 points! An atomic nucleus initially moving at 420 m/s emits an alpha particle in the direction of its velocity, and the remai
alexandr1967 [171]

The alpha particle is emitted at 4235 m/s

Explanation:

We can use the law of conservation of momentum to solve the problem: the total momentum of the original nucleus must be equal to the total momentum after the alpha particle has been emitted. Therefore:

p_i = p_f\\ Mu=m_1 v_1 + m_2 v_2 =  

where:  

M =222u is the mass of the original nucleus

v=420 m/s is the initial velocity of the nucleus

m_1 = 4 u is the mass of the alpha particle

v_1 is the final velocity of the alpha particle

m_2 = 222u-4u = 218 u is the mass of the daughter nucleus

v_2 = 350 m/s is the final velocity of the nucleus

Solving for v_1, we  find the final velocity of the alpha particle:

v_1 = \frac{Mu-m_2 v_2}{m_1}=\frac{(222)(420)-(218)(350)}{4}=4235 m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

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#LearnwithBrainly

4 0
3 years ago
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

T = 2 \pi \sqrt{\frac{m}{k} } \\

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} =  \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k =  17.71N/m

Hence the force constant of the spring is 17.71N/m

4 0
3 years ago
Why are SI units helpful for describing objects? A. They are the standard used by scientists worldwide. B. They are more accurat
Ganezh [65]

They are the standard system used by scientists worldwide, and
officially by almost all nations of the world.  So if you describe a
measurement in terms of SI units, there's less chance that you'll
need to explain the measurement to anyone who reads it ...
most scientists and common people worldwide will understand
what your number means.

7 0
3 years ago
A child is riding a merry-go-round, which has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745
Elena L [17]

w = instantaneous angular speed = 1.25 rad/s

r = radius = 4.65 m

α = angular acceleration = 0.745 rad/s²

centripetal acceleration is given as

a_{c} = rw²

a_{c} = (4.65 ) (1.25)² = 7.27 m/s²

tangential acceleration is given as

a_{t} = rα

a_{t} =4.65 x 0.745 = 3.46 m/s²

angle is given as

\theta = tan^{-1}(\frac{a_{c}}{a_{t}})

\theta = tan^{-1}(\frac{7.27}{3.46})

\theta = 64.5 deg

5 0
4 years ago
Whta is the mechanical advantage when the effort force is 20 and the resistance force is 5
pogonyaev
The mechanical advantage would be 4. 20/5=4
7 0
3 years ago
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