Answer:
How far horizontally from point A does the ball hit the floor d= 5 m
Explanation:
By law of conservation of energy we can say that
final Kinetic energy kf+ final potential energy Uf= initial Kinetic energy ki+ initial potential energy Ui
We know that the ball has Uf, the ball at the bottom and no Ki ,the ball at initial state
therefore,
Kf= Ui
therefore,
MOI for Solid ball =
=
Now substituting the values to get value of V
V= 7.48 m/s
now to calculate How far horizontally from point A does the ball hit the floor
h=
2=
t=0.6385 sec
now horizontal distance d= vt = 0.6385×7.48= 5.00 m
Answer:
Initial velocity (u) = 40 m/s
Distance travel in last 5 seconds = 100 m
Explanation:
Given:
Acceleration (a) = 8 m/s²
Final velocity (v) = 0 m/s
Find;
1] Initial velocity before 5 sec
2] Distance travel in last 5 seconds
Computation:
1] Initial velocity before 5 sec
v = u + at
0 = u + (-8)(5)
u - 40 = 0
Initial velocity (u) = 40 m/s
2] Distance travel in last 5 seconds
s = ut + (1/2)(a)(t²)
s = (40)(5) + (1/2)(-8)(5²)
s = 200 - 100
Distance travel in last 5 seconds = 100 m
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