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4 years ago

X^2 - 10x + 21 / x^2 -6x -7

Mathematics

2 answers:

fgiga [73]4 years ago

8 0

Answer:

$\frac{x-3}{x+1}$

Step-by-step explanation:

Given

$\frac{x^2-10x+21}{x^2-6x-7}$ ← factorise numerator/ denominator

x² - 10x + 21 = (x - 7)(x - 3)

x² - 6x - 7 = (x - 7)(x + 1)

The expression can be written as

= $\frac{(x-7)(x-3)}{(x-7)(x+1)}$ ← cancel the common factor (x - 7) on numerator/denominator

= $\frac{x-3}{x+1}$

svp [43]4 years ago

8 0

Answer:

$\frac{x-3}{x+1} }$

Step-by-step explanation:

if you factor both of the functions you will get

$\frac{(x-3)(x-7)}{(x-7)(x+1)}$

the two (x-7) will cancel out and you will b left with

$\frac{\\(x-3)}{(x+1)}$

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Answer:

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2 years ago

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WINSTONCH [101]

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3 years ago

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nexus9112 [7]

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3 years ago

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