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I am Lyosha [343]
3 years ago
10

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista

nce in 4.5 h. Car B traveled 5 mph slower than Car A.
How fast did Car B travel?
Mathematics
1 answer:
poizon [28]3 years ago
8 0
The rate of Car A is x
The rate of Car B is x - 5

They travel the same distance. So we can make an equation:

4(x) = 4.5(x-5)

Solve for x.

4(x) = 4.5(x-5)
4x = 4.5x - 22.5

Subtract 4.5x on both sides

-0.5x = -22.5

Divide by -0.5 on both sides
x = 45

But we want the speed of Car B which is x - 5

So Car B's speed is 45 - 5 = 40

Your answer is 40
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ahrayia [7]

Step-by-step explanation:

first u need to pick a random coordinate to substitute the X . example 0

y = 2(0) + 1

y =1 , X= 0

X= 1

y= 2(1) + 1

y= 3, X= 1

then you continue this same process and again until u have at least two points to draw a straight line. it kinda depended if u want to fill the entire graph.

3 0
3 years ago
GARY DREW A RECTANGLE WITH A PERIMETER OF 20 INCHES. WHAT COULD BE THE LENGTH,WIDTH,AND AREA FOR THE RECTANGLE THAT GARY DREW?
Ilia_Sergeevich [38]
Assume L=1.5W, where W=width, L= Length of the triangle.

Therefore,

Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in

Then, L=1.5W = 1.5*4 = 6 in

Area, A= L*W = 6*4 = 24 in^2
8 0
3 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
Solve the equation. Check your solution. - 6y + 5 = 29y - 2​
mr_godi [17]

Answer:

y = 0.2

Step-by-step explanation:

Simplifying

-6y + 5 = 29y + -2

Reorder the terms:

5 + -6y = 29y + -2

Reorder the terms:

5 + -6y = -2 + 29y

Solving

5 + -6y = -2 + 29y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-29y' to each side of the equation.

5 + -6y + -29y = -2 + 29y + -29y

Combine like terms: -6y + -29y = -35y

5 + -35y = -2 + 29y + -29y

Combine like terms: 29y + -29y = 0

5 + -35y = -2 + 0

5 + -35y = -2

Add '-5' to each side of the equation.

5 + -5 + -35y = -2 + -5

Combine like terms: 5 + -5 = 0

0 + -35y = -2 + -5

-35y = -2 + -5

Combine like terms: -2 + -5 = -7

-35y = -7

Divide each side by '-35'.

y = 0.2

Simplifying

y = 0.2

3 0
3 years ago
Read 2 more answers
Find 3/5 - 1/4 <br><br> a 4/9<br><br> b 1/2<br><br> c 2<br><br> d 7/20
Lubov Fominskaja [6]

Answer:

7/20

Step-by-step explanation:

Hope this helped!

7 0
3 years ago
Read 2 more answers
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