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gavmur [86]
3 years ago
8

Can 7/30 be reduced?

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

no

Step-by-step explanation:

as 7 is a prime numbers and prime numbers cannot be reduced .

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The height of a cone-shaped statue is 9 ft, and the diameter is 4 ft.
bogdanovich [222]
<span>37.7
The formula is </span>V=<span><span>π<span>r^2*</span></span><span>h/3, and since r is 4/2, you multiply it by </span></span><span><span>π and then multiply it h/3, which is 9/3, so ((2*3.14)*3)= 37.7.</span></span>
5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs, In the figure, lines H and KL are parallel. TH K E G D Match each ang
xz_007 [3.2K]

The angle relationship and their reasons are:

  • m∠HED = m∠FEJ ---> Vertical angles theorem
  • m∠KFE = m∠DEH ---> Alternate interior angles theorem
  • m∠LFG = m∠DEH ---> Alternate exterior angles theorem
  • m∠JEF + m∠LFE = 180° ---> same-side interior angles theorem
  • m∠DEJ = m∠EFL ---> Corresponding interior angles theorem
  • m∠LFG + m∠GFK = 180 ---> linear pair

The angle pairs are formed based on their relative positions. The following shows each angle relationship and their reasons:

∠HED and ∠FEJ are directly vertically opposite each other, therefore, they are  equal based on the vertical angles theorem.

  • m∠HED = m∠FEJ ---> Vertical angles theorem

∠KFE and ∠FEJ are alternate interior angles, therefore, they are  equal based on the alternate interior angles theorem.

  • m∠KFE = m∠DEH ---> Alternate interior angles theorem

∠LFG and ∠FEJ are alternate exterior angles, therefore, they are  equal based on the alternate exterior angles theorem.

  • m∠LFG = m∠DEH ---> Alternate exterior angles theorem

∠JEF and ∠LFE are interior angles on same side of the transversal, therefore, the sum of both angles equal 180 degrees based on the same-side interior angles theorem.

  • m∠JEF + m∠LFE = 180° ---> same-side interior angles theorem

∠DEJ and ∠EFL are corresponding angles, therefore, they are  equal based on the corresponding angles theorem.

  • m∠DEJ = m∠EFL ---> Corresponding interior angles theorem

∠LFG and ∠GFK are angles on a straight line, therefore the sum of both angles will equal 180 degrees because they are a linear pair.

  • m∠LFG + m∠GFK = 180 ---> linear pair

Learn more about angle relationship on:

brainly.com/question/12591450

4 0
2 years ago
The radius of a circle is 10 cm. Find its circumference in terms of pi
sergejj [24]

Answer:

20 pi is the correct answer

5 0
3 years ago
True or false: the standard deviation of a set of data values is never a negative number
Anestetic [448]
True I think !! Not to sure
8 0
3 years ago
Find the Fourier series of f on the given interval. f(x) = 1, ?7 &lt; x &lt; 0 1 + x, 0 ? x &lt; 7
Zolol [24]
f(x)=\begin{cases}1&\text{for }-7

The Fourier series expansion of f(x) is given by

\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7

where we have

a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx
a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)
a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2

The coefficients of the cosine series are

a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx
a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)
a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}
a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}

When n is even, the numerator vanishes, so we consider odd n, i.e. n=2k-1 for k\in\mathbb N, leaving us with

a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}

Meanwhile, the coefficients of the sine series are given by

b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx
b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)
b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}
b_n=\dfrac{7(-1)^{n+1}}{n\pi}

So the Fourier series expansion for f(x) is

f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7
3 0
3 years ago
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