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3 years ago

Need help on this please

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

25 $\pi$

Step-by-step explanation:

$\pi$ $r^{2}$ =area of circle

$\frac{1}{4}$ $\pi$ $r^{2}$ =1/4 of the area of a circle

now solve

$\frac{1}{4}$ $\pi$ $10^{2}$

$\frac{1}{4}$ $\pi$ 100

25 $\pi$

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Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

6 0

3 years ago

Read 2 more answers

Aless and Louis are going to put a rectangular pool in their backyard. The cost of installation is $6,000. If the dimensions of

lana [24]

Answer:

cost of the pool per cubic meters = $5

Step-by-step explanation:

The rectangular pool has a dimension of 30 m by 20 m by 2 m. To know the cost of the pool per cubic meter we have to calculate the volume of the pool . Then divide the total cost of the pool by it volume.

volume of the rectangular pool = length × height × width

volume of the rectangular pool = 30 × 20 × 2

volume of the rectangular pool = 1200 m²

The cost of installation is $6000 . The volume of the pool is 1200 cubic meters.

cost per cubic meters = total cost of installation/volume

cost per cubic meters = 6000/1200

cost of the pool per cubic meters = $5

7 0

3 years ago

This is a valid probability distribution because if you add together the probabilities their sum is 1

abruzzese [7]

Answer:

True

Step-by-step explanation:

7 0

2 years ago

8. Patrice and Don buy a home for $92,000. The property tax rate is$39.50 per $1,000 of assessed value. The assessment rate is 4

Kaylis [27]

We start by calculating the assessed value, that is 41% of the price.

The price is $92,000.

Then, the assessed value is:

$AV=a\cdot P=\frac{41}{100}\cdot92000=0.41\cdot92000=37720$

The property tax rate is $39.50 per $1000 of assessed value, so we can express this rate as:

$\text{tax rate}=\frac{39.50}{1000}=0.0395$

We then can multiply this rate by the assessed value to calculate the total property tax:

$\text{tax}=0.0395\cdot37720=1489.94$

NOTE: we could have also multiplied 39.50 by 37.72. The value 37.72 is the thousands of dollars of assessed value. We would have obtained the same result: 39.50*37.72=1489.94.

Answer: the property tax is $1,489.94.

3 0

1 year ago

Find the 5th term of the sequence in which T1=8 and Tn=3t n-1

yan [13]

T_n = 3 * T_(n-1)

Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1

T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!

Short way (sometimes it works!)

T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648

6 0

3 years ago