1)
Julia = Sj = 30,500 + 500n
Aysha = Sa = 26,000 + 1000n
when will
Sj = Sa
30,500 + 500n = 26,000 + 1000n
30,500 - 26,000 = 1000n - 500n
4,500 = 1000n - 500n
4,500 = 500n
n = 9
so they will have same salary after 9 years
2) X + Y = 8000
5%X + 3.25%Y = 312.5
X = 8000 - Y
0.05 ( 8000 - Y ) + 0.0325Y = 312.5
400 - 0.05Y + 0.0325Y = 312.5
400 - 0.0275Y = 312.5
400 - 312.5 = 0.0275Y
87.5 = 0.0275Y
Y = 3,181.81
X = 8000 - Y = 8000 - 3,181.81 = 4,818.19
3) X + Y = 3050
8%X + 7.5%Y = 234
X = 3050 - Y
0.08(3050 - Y) + 0.075Y = 234
244 - 0.08Y + 0.075Y = 234
244 - 234 = 0.025Y
Y = 400
X = 3050 - Y = 3050 - 400 = 2650
Expanding it, we get 1.3*8-1.3b+3.7b=-5.2 using the distributive property. Next, we get 10.4+2.4b=-5.2. Subtracting 10.4 to both sides, we get -15.6=2.4b. Dividing 2.4 from both sides, we get b=-15.6/2.4=-6.5
The missing number is 6 because half of 18 is 9 and half of 12 is 6
Answer:
[μ-error, μ + error]
[14000- 3000, 14000 + 3000]
Step-by-step explanation:
We write it how an interval, where the center of the interval is the mean, thus
[μ-error, μ + error]
First we calculate the mean
μ = (11000+17000)/2
μ = $14000
And the error is the absolute value of the difference between the mean an either extreme values
error = |14000 -17000| = |14000 - 11000| = 3000
Then
[14000- 3000, 14000 + 3000]