The correct answer is the last statement.
If the regulatory serine is mutated to alanine, then acetyl-CoA carboxylase will get activated spontaneously and will produce malonyl-CoA. The increased concentrations of malonyl-CoA will obstruct the oxidation of fatty acids by preventing the entry of fatty acids into the mitochondria.
It is because the AMP-activated protein kinase phosphorylates the serine residues of acetyl-CoA carboxylase to inactivate it. If a mutation occurs in such residues, then the AMPL cannot phosphorylate acetyl-CoA carboxylase and this enzyme will get activated spontaneously.
In such a situation, there will be more than sufficient production of malonyl-CoA, which will inhibit the admittance of more fatty acid getting inside the mitochondria; this will indirectly prevent the oxidation of fatty acids.
The sequence AAU GGC UAC is composed of three codons each of which codes for a different amino acid.
AAU codes for the amino acid called threonine.
GGC codes for the amino acid called glycine
UAC codes for the amino acid called tyrosine.
So the chain will read threonine-glycine-tyrosine.
There are 64 possible 3 - letter combinations of DNA coding units A, C, G and T. Of these, there are three stop or non- sense codons that do not code for any amino acid, while the remaining 61 code for different amino acids.
Some plants are able to withstand extreme weather conditions
(1) All the genotypes are as follows: AABB, AaBB, AABb, AaBb, aaBB, aaBb, AAbb, Aabb, aabb.
(2) Assuming that Aa is dominant and Bb is recessive, there will be 9 phenotypes with both A and B allele dominant (i.e. AaBb, AABb); there will be 3 phenotypes with just the A allele dominant (i.e. Aabb, AAbb); there will be 3 phenotypes with just the B allele dominant (i.e. aaBb, aaBB); and there will be 1 phenotype with both alleles recessive (i.e. aabb). The phenotypic ratio in this case is 9:3:3:1.
(3) The probability of producing an offspring with the aabb genotype is 1/16 or 6%.