Question

Which function has real zeros at x=-8 and x=5?​

Answer 1

Answer:

The answer is A

Step-by-step explanation:

Answer 2

Answer: The required function would be $x^2+3x-40$

Step-by-step explanation:

Since we have given that

There are two real zeroes :

x = -8 and x = 5

So, we need to find the function satisfying the above two zeroes:

Let α = -8 and β = 5

So, it means it is a quadratic equation :

$x^2-(\alpha +\beta)x+\alpha \beta \\\\=x^2-(-8+5)x+-8\times 5\\\\=x^2+3x-40$

Hence, the required function would be $x^2+3x-40$