El garage "Bolivar" tiene3 pisos. En el primero hay 5 filas con 20 lugares en cada una. En el segundo y en el tercero, 4 filas c
1 answer:
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1. Horizontal asymptotes: None
Vertical asymptote: x=-2
RD: 2
Domain: First picture
Range: first pic
2.HA: y=1
VA: x= -5 negative
RD: x= 5 no negative
Domain: second pic
Range second pic
3.HA: y=0
VA: x=-4,4
RD: none
D: 3rd pic
R: 3rd pic
4.HA: none
VA: x=3
RD: x=-2
D: 4th
R: 4th
I hope this helps!!!!!!!
Vertical asymptote: x=-2
RD: 2
Domain: First picture
Range: first pic
2.HA: y=1
VA: x= -5 negative
RD: x= 5 no negative
Domain: second pic
Range second pic
3.HA: y=0
VA: x=-4,4
RD: none
D: 3rd pic
R: 3rd pic
4.HA: none
VA: x=3
RD: x=-2
D: 4th
R: 4th
I hope this helps!!!!!!!
(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.
(b) two eigen values of 'k' = 1, -1
for k = 1, eigen vector is
for k = -1 eigen vector is
See the figure for the graph:
(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )
∴ x → -x hence '-1' is the eigen value.
∴ y → y hence '1' is the eigen value.
also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.
( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.
(b) ∵ T(x, y) = (-x, y)
T(x) = -x = (-1)(x) + 0(y)
T(y) = y = 0(x) + 1(y)
Matrix Representation of
now, eigen value of 'T'
after solving the determinant,
we get two eigen values of 'k' = 1, -1
for k = 1, eigen vector is
for k = -1 eigen vector is
Hence,
(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.
(b) two eigen values of 'k' = 1, -1
for k = 1, eigen vector is
for k = -1 eigen vector is
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