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umka2103 [35]
3 years ago
8

What are 3 physical properties of aluminum foil

Chemistry
1 answer:
adell [148]3 years ago
4 0
Solid, ductile (can conduct heat), malleable (can be shaped differently).
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Balance the equation and state the limiting reagent in the following reaction:
romanna [79]
Hgffvvcbchcgivigcigxgsgixigdfhcgcc fcfuc
8 0
3 years ago
23
grigory [225]

Answer:

The anser is C

Explanation:

This is because the fungi and bacteria are the decomposer, and their job is to decompose dead organism.

7 0
3 years ago
Read 2 more answers
If 200. g of water at 20°C absorbs 41 840 J of energy, what will its final temperature be? (Specific Heat of water is 4.184 J/g*
Elena-2011 [213]

Answer: The final temperature will be 70^0C

Explanation:

To calculate the specific heat of substance during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed =41840 J

c = specific heat = 4.184J/g^0C

m = mass of water  = 200 g

T_{final} = final temperature =?

T_{initial}= initial temperature = 20^0C

Now put all the given values in the above formula, we get:

41840J=200g\times 4.184J/g^0C\times (T_{final}-20)^0C

T_{final}=70^0C

Thus the final temperature will be 70^0C

3 0
3 years ago
What is the difference in mesomeric and electromeric effect​
Leya [2.2K]

Cause their are both have difference s

8 0
3 years ago
Question 3 0
Tanya [424]

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

5 0
3 years ago
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