All categories

3 years ago

1. What makes a plant vacuole different from an animal vacuole? |

Chemistry

1 answer:

Olenka [21]3 years ago

5 0

Answer:

O Plant vacuoles are large and animal vacuoles are small

I hope this helps

You might be interested in

I'll give brainliest why the total energy of electron is negative

kramer

Answer:

Electrons are always marked negative Hence electronic energy is also always taken as negative. It is because when an electron is at infinite distance from nucleus , there the kinetic energy of that electron can not be calculated. So, it is taken to be zero . ... And thus the energy of electron becomes less negative

5 0

4 years ago

Starting with 9.3 moles of O2, how many moles of H2S will be needed and how many moles of SO2 will be produced in the following

tensa zangetsu [6.8K]

Answer: The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

Explanation:

We are given:

Moles of oxygen gas = 9.3 moles

The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:

$2H_2S+3O_2\rightarrow 2SO_2+2H_2O$

For hydrogen sulfide:

By Stoichiometry of the reaction:

3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide

So, 9.3 moles of oxygen gas will react with = $\frac{2}{3}\times 9.3=6.2mol$ of hydrogen sulfide

For sulfur dioxide:

By Stoichiometry of the reaction:

3 moles of oxygen gas produces 2 moles of sulfur dioxide

So, 9.3 moles of oxygen gas will produce = $\frac{2}{3}\times 9.3=6.2mol$ of sulfur dioxide

Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

7 0

3 years ago

How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?

Nina [5.8K]

11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=298 K

Putting value in the given equation:

$\frac{PV}{RT}=n$

$n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}$

Moles = 0.3588 moles

Now,

$Moles = \frac{mass}{molar \;mass}$

$0.3588 moles = \frac{mass}{32}$

Mass= 11.48 gram

Hence, 11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0

2 years ago

What is the specific heat capacity of a metal if it requires 177.5 J to change the temperatures of 15.0g of the metal from 25.00

Vikentia [17]

Answer:

The specific heat capacity of a metal is 1.31 J/g°C = C

Explanation:

A classical excersise of calorimetry to apply this formula:

Q = m . C . ΔT

177.5 J = 15 g . C (34°C - 25°C)

177.5 J = 15g . 9°C . C

177.5 J /15g . 9°C = C

1.31 J/g°C = C

3 0

3 years ago

Calculate the specific heat for as air if 1500.0 joules are required to raise the temperature of 50.0g from 0.0c to 40.0c

Law Incorporation [45]

The specific heat, c is 0.75 J/g°C

Explanation:

Heat or Energy, Q = 1500J

Mass, m = 50g

T1 = 0°C

T2 = 40°C

Specific Heat, c = ?

We know,

Q = mcΔT

Q = mc(T2-T1)

1500 = 50 X c X (40-0)

1500 = 50 X c X 40

c = 1500/ 2000

c = 0.75 J/g°C

Therefore, the specific heat, c is 0.75 J/g°C

7 0

3 years ago