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max2010maxim [7]
3 years ago
6

How many liters of oxygen are in 8.32 moles of oxygen at STP

Chemistry
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

186 Liters at STP conditions

Explanation:

1 mole of any gas at STP conditions occupies 22.4 Liters.

Therefore, 8.32 moles O₂(g) = 8.32 moles x 22.4Liters/mole = 186 Liters (3 sig.figs.)

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Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points from highest to l
muminat

Answer:

NH4Cl > Li2SO4 > CoCl3

Explanation:

Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.

Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.

Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.

4 0
3 years ago
4. Calculation of theoretical yield and percent yield You balanced this reaction earlier: Mg(s) + HCl (aq) H2 (g) + MgCl2 (aq) Y
erik [133]

Answer:

Mg(s) +<em> 2</em> HCl (aq) →  H₂(g) + MgCl₂

0.415g of H₂(g) <em>-Assuming mass of Mg(s) = 10.0g-</em>

Explanation:

Balancing the reaction:

Mg(s) + HCl (aq) →  H₂(g) + MgCl₂

There are in products two atoms of H and Cl, the balancing equation is:

Mg(s) +<em> 2</em> HCl (aq) →  H₂(g) + MgCl₂

<em>Assuming you add 10g of Mg(s) -Limiting reactant-</em>

<em />

10g of Mg are (Atomic mass: 24.305g/mol):

10g × (1 mol / 24.305g) = <em>0.411 moles of Mg</em>

<em>-Theoretical yield is the amount of product you would have after a chemical reaction occurs completely-</em>

Assuming theoretical yield, as 1 mole of Mg(s) produce 1 mole of H₂(g), theoretical yield of H₂(g) is 0.411moles H₂(g). In grams:

0.411mol H₂(g) × (1.01g / mol) = <em>0.415g of H₂(g)</em>

3 0
3 years ago
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