Answer: The partial pressure of oxygen is 76.56 atm , partial pressure of carbon dioxide is 10.44 atm and the total pressure is 87 atm.
Explanation:
According to the ideal gas equation:'
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
P = Pressure of the gas = ?
V= Volume of the gas =
![1L=1000cm^3](https://tex.z-dn.net/?f=1L%3D1000cm%5E3)
T= Temperature of the gas = 10°C = 373 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= 0.25 +0.034 = 0.284 moles
![P=\frac{nRT}{V}=\frac{0.284\times 0.0821\times 373}{0.1}=87atm](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BnRT%7D%7BV%7D%3D%5Cfrac%7B0.284%5Ctimes%200.0821%5Ctimes%20373%7D%7B0.1%7D%3D87atm)
= mole fraction of oxygen=
,
=mole fraction of carbon dioxide=![\frac{\text {moles of }CO_2}{\text {moles of }O_2+\text{moles of }CO_2}=\frac{0.034}{0.25+0.034}=0.12](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bmoles%20of%20%7DCO_2%7D%7B%5Ctext%20%7Bmoles%20of%20%7DO_2%2B%5Ctext%7Bmoles%20of%20%7DCO_2%7D%3D%5Cfrac%7B0.034%7D%7B0.25%2B0.034%7D%3D0.12)
partial pressure of oxygen = ![p_{O_2}=x_{O_2}\times P=0.88\times 87=76.56atm](https://tex.z-dn.net/?f=p_%7BO_2%7D%3Dx_%7BO_2%7D%5Ctimes%20P%3D0.88%5Ctimes%2087%3D76.56atm)
partial pressure of carbon dioxide= ![p_{CO_2}=x_{CO_2}\times P=0.12\times 87=10.44atmatm](https://tex.z-dn.net/?f=p_%7BCO_2%7D%3Dx_%7BCO_2%7D%5Ctimes%20P%3D0.12%5Ctimes%2087%3D10.44atmatm)
The partial pressure of oxygen is 76.56 atm , partial pressure of carbon dioxide is 10.44 atm and the total pressure is 87 atm.
The electron configuration for N is 1s^2 2s^2 2p^3, or it could be [He]2s^2 2p^3 but you don’t have the diagram out so I can’t say the definite answer
The binding energy is calculated from the product of the mass defect and the square of the speed of light. First, we need to calculate for the mass defect. We do as follows:
m = mass products - mass of reactantsm = 33*1.00867 + 27*1.00728 - 59.9338 m = 0.54887
E = mc^2 = 0.54887 (3x10^8)^2 = 4.94x10^16 J
Answer : Option A) its 3d orbital is completely filled.
Explanation : Arsenic does not have any valence electrons in the 3d orbital because it's 3d orbital is completely filled.
Arsenic has atomic number as 33 and the electron configuration is
. It clearly shows that the 3d orbital is completely filled which does not has space to accommodate any electrons in the 3d orbital. Therefore, the electrons are accommodated in 4s and 4p orbitals,
The answer is "<span>the number of moles of H+ ions equals the number of moles of OH– ions "</span>