Which one is the answer... a, b, or c?

Calculate the whole-number ratio of staggered to eclipsed conformers that are present at room temperature. Use the Actual G˚ bar

natka813 [3]

Answer:

The ratio of staggered to eclipsed conformers is 134

Explanation:

It is possible to determine the ratio of staggered to eclipsed conformers of a reactant, using the equilibrium:

Staggered ⇄ Eclipsed

Keq = [Eclipsed] / [Staggered]

That means Keq is equal to the ratio we need to find:

Using:

G˚= -RTln Keq

<em>Where G° = -12133.6J/mol</em>

<em>R is gas constant: 8.314J/molK</em>

<em>T is absolute temperature: 298K</em>

<em />

-12133.6J/mol= -8.314J/molK*298K ln Keq

4.8974 = ln Keq

134 = Keq = [Eclipsed] / [Staggered]

<h3>The ratio of staggered to eclipsed conformers is 134</h3>

3 0

2 years ago

Please i needed but Good

dsp73

It's 48 cubic meters

6 0

3 years ago

3. During an experiment where 50.0 mL of a 1.0 M acid solution was mixed with 50.0 mL of a 1.0 M base solution, the temperature

Aleksandr-060686 [28]

Answer:

$\large \boxed{\text{-61 kJ$\cdot$mol$^{-1}$}}$

Explanation:

Data:

H₃O⁺ + OH⁻ ⟶ 2H₂O

V/mL: 50.0 50.0

c/mol·L⁻¹: 1.0 1.0

ΔT = 6.5 °C

ρ = 1.210 g/mL

C = 4.18 J·°C⁻¹g⁻¹

C_cal = 12.0 J·°C⁻¹

Calculations:

(a) Moles of acid

$\text{Moles of acid} = \text{0.0500 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{0.0500 mol}\\\\\text{Moles of base} = \text{0.0500 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{0.0500 mol}$

(b) Volume of solution

V = 50.0 mL + 50.0 mL = 100.0 mL

(c) Mass of solution

$\text{Mass of solution} = \text{100.0 mL} \times \dfrac{\text{1.10 g}}{\text{1 mL}} = \text{110.0 g}$

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

nΔH + mCΔT + C_calΔT = 0

0.0500ΔH + 1.10×4.18×6.5 + 12.0×6.5 = 0

0.0500ΔH + 2989 + 78.0 = 0

0.0500ΔH + 3067 = 0

0.0500ΔH = -3067

ΔH = -3067/0.0500

= -61 000 J/mol

= -61 kJ/mol

$\text{The enthalpy of reaction is $\large \boxed{\textbf{-61 kJ$\cdot$mol$^{\mathbf{-1}}$}}$}$

Note: The answer can have only two significant figures because that is all you gave for the change in temperature.

7 0

2 years ago

What is your standing regarding compostable plastics? Is it really environmental-friendly?

Archy [21]

If a biodegradable plastic or bioplastic ends up in a landfill site it will never decompose. In landfill sites waste is essentially mummified, in a complete absence of light and oxygen. Food that has ended up in landfill will not biodegrade, so there is no hope for biodegradable plastics or even bioplastics.So it is bad.

6 0

2 years ago

.A person is unable to see distinctly the objects placed at large distances but is able to read a book comfortably. Name the def

GaryK [48]

Answer:

The defect of vision suffered by the person is Myopia

Explanation:

The person can't see farther objects but is able to read a book which is placed closely to the eyes, using these observations the person is suffering from MYOPIA(nearsightedness) in which observer see close objects clearly but farther objects appear blurred.

The light entering the eye isn't correctly bent, the eyeball becomes big , or the eye lens become too converging, which converges the light ray in front of the cornea

This defect can be cured by using concave lenses.

7 0

2 years ago