Answer : The molar heat of solution of KCl is, 17.19 kJ/mol
Explanation :
First we have to calculate the heat of solution.
where,
q = heat produced = ?
c = specific heat capacity of water = 
= change in temperature = 0.360 K
Now put all the given values in the above formula, we get:
Now we have to calculate the molar heat solution of KCl.
where,
= enthalpy change = ?
q = heat released = 460.8 J
m = mass of 
= 2.00 g
Molar mass of = 74.55 g/mol
Now put all the given values in the above formula, we get:
Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol
In this lab activity, a solution of gum arabic was added to a solution of gelatin to form coacervates<span>. Gum arabic is made up of </span>carbohydrate macromolecules<span> while gelatin is made up of </span>protein macromolecules<span>. this lab show how the earth was formed from many different molecules.</span>
<span>the answer is
2.7 moles
</span>
Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
= freezing point constant =
m= molality = 
Let Mass of solute (KBr) = x g
Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
