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dezoksy [38]
3 years ago
8

1. Write the chemical equation when excess chloride ion is added to aqueous solution of cobalt chloride. Note observed color of

each complex ion. 2. What is the likely composition of the solution when the intermediate or transition color is reached? How does this provide visual proof of the idea that not all reaction go to completion?
3. Use LeChatelier's principle to explain the color changes observed upon addition of water and calcium chloride to an equilibrium mixture of the two complex ions in this reaction. 4. What was the effect of adding AgNO3 on the position of equilibrium for these two complex ions? Is this effect consistent with LeChatelier's Principle.
Chemistry
1 answer:
Aneli [31]3 years ago
5 0

The element cobalt can form compounds in two different oxidation states, +2 and +3. 


The +2 state is more common.

The ion Co2+ (aq) is pink.

Other compounds of cobalt(II), which include both anhydrous Co2+ and complex ions, are commonly blue.

If an aqueous solution contains both cobalt(II) and chloride ions, the blue ion CoCl42- forms, in equilibrium with the pink Co2+ (aq) ion.

<span>CoCl42- (aq) <===========> Co2+ (aq) + 4Cl1-(aq)</span>

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<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is _{53}^{131}\textrm{I}

<u>For b:</u> The isotopic representation of cesium is _{55}^{137}\textrm{Cs}

<u>For c:</u> The isotopic representation of strontium is _{38}^{52}\textrm{Sr}

<u>Explanation:</u>

The isotopic representation of an atom is: _Z^A\textrm{X}

where,

Z = Atomic number of the atom

A = Mass number of the atom

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  • <u>For a:</u>

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is _{53}^{131}\textrm{I}

  • <u>For b:</u>

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is _{55}^{137}\textrm{Cs}

  • <u>For c:</u>

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is _{38}^{52}\textrm{Sr}

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