The distributive property....ur basically multiplying the number outside of the parenthesis by everything in the parenthesis....to get rid of the parenthesis.
9(2 + 5m) = (9 * 2) + (9 * 5m) = 18 + 45m <==
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
It is 1130.1 hope this helps
You can take it apart. There are a top and bottom (both the same) right triangle. So you can find the area of that by multiplying 8*6 and divide by two. Then multiply by two because there are 2 triangles.
You are left with three rectangular sides: One 10x10, one 10x6, and one 10x8.
So your whole equation looks like this: A = 2[(8*6)/2]+(10*10)+(10*6)+(10*8)
Answer:
The minimum cost is $9,105
Step-by-step explanation:
<em>To find the minimum cost differentiate the equation of the cost and equate the answer by 0 to find the value of x which gives the minimum cost, then substitute the value of x in the equation of the cost to find it</em>
∵ C(x) = 0.5x² - 130x + 17,555
- Differentiate it with respect to x
∴ C'(x) = (0.5)(2)x - 130(1) + 0
∴ C'(x) = x - 130
Equate C' by 0 to find x
∵ x - 130 = 0
- Add 130 to both sides
∴ x = 130
∴ The minimum cost is at x = 130
Substitute the value of x in C(x) to find the minimum unit cost
∵ C(130) = 0.5(130)² - 130(130) + 17,555
∴ C(130) = 9,105
∵ C(130) is the minimum cost
∴ The minimum cost is $9,105
