Answer:
<em>Thus, the dimensions of the desk in the drawing are 4 cm long and 2 cm wide.</em>
Step-by-step explanation:
<u>Scaling</u>
The scale factor established to represent a desk 2 meters long and 1 meter wide is:
1 centimeter = 0.5 meter
We need to convert the real dimensions to the scaled dimensions. To complete the task, it's a good idea to multiply the real dimensions by the ratio:

to get the scaled dimensions.
The length of 2 meters is scaled to:

And the width of 1 meter is scaled to:
\displaystyle 1\ m\frac{1\ cm}{0.5\ m}=2 cm
Thus, the dimensions of the desk in the drawing are 4 cm long and 2 cm wide.
So the equation of a circle is (x - h)² + (y - k)² = r² where (h,k) are the coordinates of the center of the circle and r is the radius. The diameter of a circle is a line that goes from one point of the circle to the other through the center of the circle. Well the center would be midway through the diameter so use midpoint formula to find the center which is (h,k) Mid point formula is both given x's added together divided by 2 for h and both y coordinates added together divided by 2 to find k
(10+0)/2
10/2= 5
(12+2)/2
14/2 = 7
so the center of the circle is (5,7) now use distance formula using the center and one of the points to the radius
√((5-10)²+(7-12)²)
√(-5²+ -5²)
√(25 + 25)
√50 is the radius
Now plug all found information into circle equation
(x-5)² + (y-7)² =50 note the end is 50 because the circle equation is radius squared and since the radius is √50, radius² is 50.
Answer is c
Answer:
= - 1.5n - 6
Step-by-step explanation:
Given that the sequence is arithmetic with n th term ( explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 7.5 and d = - 9 - (- 7.5) = - 9 + 7.5 = - 1.5
= - 7.5 - 1.5(n - 1) = - 7.5 - 1.5n + 1.5 = - 1.5n - 6
Step-by-step explanation:
The answer is 81/16 simply
"<span>all real numbers between 3 and 10 inclusive" could not be the answer, because these are x-values (values of the independent variable).
"</span><span>all real numbers between 19 and 54 inclusive" is the range. Why? Because in year 3, f(3) = height of tree = 5(3) + 4 = 19 feet.
In year 10, f(10) = 5(10) + 4 = 54 feet. </span>