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Morgarella [4.7K]

3 years ago

12

What is the inverse of the function

" id="TexFormula1" title="f(x) = \frac{x + 1}{x} " alt="f(x) = \frac{x + 1}{x} " align="absmiddle" class="latex-formula">

1 answer:

expeople1 [14]3 years ago

3 0

Y=(x+1)/x

x=y+1 / y

x=1/(y-1)

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D ujhyjrbv6trvb5yt46y5thr

avanturin [10]

Answer:

The answer is e

Step-by-step explanation:

6 0

3 years ago

The answer is 35 degrees, but I am unsure of the process in order to get to that answer.

hammer [34]

Answer:

Step-by-step explanation:

Hello There!

So first things first

we need to find the measure of ∠ABD

If you didn´t know the sum of the triangle angles is 180

so to find ∠ABD we subtract the given angles ( 30 and 25) from 180

180-25-30=125

so angle ∠125

Now lets find ∠DBC

∠ABD and ∠ DBC are supplementary angles so the sum of the two angles is 180

So to find ∠DBC we subtract 125 from 180

180-125=55

so ∠DBC = 55

Now we can find the measure of ∠BDC

remember like stated before the sum of all of the angles in a triangle is 180

So to find the measure of ∠BDC we subtract the given angles from 180

180-90-55=35

so we could conclude that ∠BDC = 35

Other ways to solve for ∠DBC:

angle DBC is an exterior angle of ΔABD

the measure of an exterior angle is equal to the sum of the opposite interior angles

so basically ∠DBC = ∠ADB + ∠BAD

30+25=55 so ∠DBC = 55

Other ways to find angle BDC:

Having found the measure of ∠DBA and the other opposite angle we could find ∠BDC

Like stated before the measure of an exterior angle is equal to the sum of the opposite interior angles

basically ∠DBA = ∠BDC + ∠BCA

we have the measures of ∠BCA and ∠DBA so we plug in the values

125=∠BDC+90

isolate the variable by subtracting each side by 90

125-90=35

we´re left with

∠BDC=35

I hope this helps and if you have anymore questions, feel free to ask! :)

4 0

3 years ago

Read 2 more answers

The expression 36 ÷ 6 • 2 + 1 is equal to _____.<br><br> 2<br> 4<br> 13<br> 18

NeTakaya

Answer:

Step-by-step explanation:

36/6 · 2 + 1

6 ·2 + 1

12 + 1 = 13

answer is 13

7 0

3 years ago

Can anyone help me with this?

faltersainse [42]

Answer:

a

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =

marta [7]

Answer:

The integral for the arc of length is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

By using Simpon’s rule we get: 1.5355453

And using technology we get: 2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

$\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx$

We need the derivative of the function:

$f'(x)=\frac{1}{x}$

And we need it squared:

$[f'(x)]^2=\frac{1}{x^2}$

Then the integral is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

Now, the Simposn’s rule with n=4 is:

$\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)$

In this problem:

$a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}$

So, the Simposn’s rule formula becomes:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then simplifying a bit:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then we just do those computations and we finally get the approximation via Simposn's rule:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453$

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

$\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%$

8 0

3 years ago