Answer:
Places in binary coding
1 - 2 - 4 - 8 - 16 - 32 - 64 - 128 - 256 - 512 - 1024 - 2048
2483 - 2048 = 435 there is 1 in the 2048 position
435 - 256 = 179 there is 1 in the 256 position
179 - 128 = 51 there is 1 in the 128 position
51 - 32 = 19 there is 1 in the 32 position
19 - 16 = 3 there is 1 in the 16 position
3 - 2 = 1 there is 1 in the 2 position
1 - 1 = 0 there is 1 in the 1 position
10011011 0011 would be the binary result
Check:
2048 + 0 + 0 + 256 + 128 + 0 + 32 + 16 + 0 + 0 + 2 + 1 = 2483
Answer:
2 , 3 ,4
Step-by-step explanation:
to find the right triangle use the pythagorian method
A^2+B^2= C^2
Answer:
Formula
A = 1/2 b * h
Substitute
Area = 60 in^2
b = x
h = 2x - 1
60= 1/2 * x * (2x - 1)
Solve
60 = 1/2 * x (2x - 1) Multiply by 2
60 * 2 = x(2x - 1)
120 = x (2x - 1) Remove the brackets.
120 = 2x^2 - x Subtract 120 from both sides.
2x^2 - x - 120 = 0 This factors.
(2x + 15)(x - 8) = 0
Solve for x
2x + 15 = 0
2x = - 15
x = -15/2
x = - 7.5 a negative measurement is useless. Discard this answer.
x - 8 = 0
x = 8
Area (Check)
base = 8
height = 16 - 1 = 15
Area = 1/2 * 8 * 15 = 60 as it should
Answer
Use Area = 1/2 * b * h to find the base and the height.Step-by-step explanation:
The width of the rectangle is 11.5
The mean is 21. The median is 15. The mode is 15. The range is 16.
