Answer:
me puede ayudar este deber
Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
The value of one stock would be 149
A for the first because there are 4 aces and 1 nine of hearts. that makes it 5 cards of the 52 in a deck
d for the second because there are two cards: the queen of heart and and ace of diamond out of the 52
hope this helped :)
Answer:
12.75
Step-by-step explanation:
c = π x d
40.035= 3.14 x d
40.035/3.14 = 12.75
