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3 years ago

What is the reciprocal of 7/9

1 answer:

4 0

The reciprocal of a given fraction is obtained by flipping the elements of the fraction. This means that the current numerator becomes the denominator of the reciprocal and the current denominator becomes the new numerator. Thus, for the given fraction, the reciprocal is 9/7.

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In the figure below, what is the length of PS in terms of x please help

3241004551 [841]

Answer:

B) x+22

Step-by-step explanation:

PS= PQ+QR+RS

PS= 2x+4+8+10-x

PS= x+22

Hope this helps you.

8 0

3 years ago

Read 2 more answers

Boatesville is 65 3/5 kilometers from Stanton. A bus traveling from Stanton is 24 1/3 kilometers from Boatesville. Write an equa

Elena L [17]

Distance the bus has traveled :

$65 \dfrac{3}{5} - 24\dfrac{1}{3}$

$= 65 \dfrac{3 \times 3 }{5 \times 3} - 24\dfrac{1 \times 5}{3 \times 5}$

$= 65 \dfrac{9 }{15} - 24\dfrac{5}{15}$

$= 41 \dfrac{4 }{15} \text { km}$

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$\text {Answer : The bus has traveled }41 \frac{4}{5} \text { km}$
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8 0

3 years ago

What is the missing length? 3 yd 6 yd area = 39 yd 2

insens350 [35]

Answer:

2 your welcome

Step-by-step explanation:

3 0

3 years ago

The table below shows two equations:

CaHeK987 [17]

Answer:

The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

Step-by-step explanation:

Rearranging the two equations, you get ...

|4x -3| = 9 . . . . . has two solutions
|2x +3| = -5 . . . . has no solutions (an absolute value cannot be negative)

The above-listed answer is the only one that matches these solution counts.

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Testing the above values of x reveals they are, indeed, solutions to Equation 1.

4 0

3 years ago

Read 2 more answers

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0 What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

6 0

3 years ago