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sergeinik [125]
3 years ago
14

3.6m by 1.8 m wall How many 6 cm by 6 cm pictures could fit on the wall?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0
(3.6*100)/6=60
(1.8*100)/6=30
60*30=1800
there are 1800 pictures could fit on the wall.
gladu [14]3 years ago
6 0

Answer:

1800 pictures could fit on the wall.

Step-by-step explanation:

If the area of a space is given as A and this space is to be filled by pictures of area A' then number of pictures will be = \frac{A}{A'}

Now we know area of wall is A and area of picture is A'.

Length and width of wall = 3.6×1.8 m

So area of the wall A = 3.6×1.8 = 6.48 m²

Dimensions of one picture = 6×6 cm Or 0.06×0.06 m

So are of one picture A' = 0.0036 m²

Therefore, Number of pictures on the wall = \frac{A}{A'} = \frac{6.48}{0.0036}=1800

Number of pictures required to cover the wall = 1800

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On a popular television quiz show, contestants gain points for getting questions correct, and lose points for getting the answer
xenn [34]

Answer:

A

Step-by-step explanation:

200+150+150=500

500-500=0

5 0
2 years ago
Read 2 more answers
The newspaper says the only 42% of registered voters voted to determine a school bond election. If 11,960 people voted, how many
umka2103 [35]
42% of the body voted = 11960
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7 0
3 years ago
14. The area of a rectangle is 375 square inches and it’s perimeter is 80 inches. Find both the length and width.
Pavel [41]

Answer:

Length  =25 inches

Width = 15 inches

Step-by-step explanation:

Let l = length of rectangle, w = width of rectangle

Given the area and the perimeter of the rectangle, we can write:

lw = 375

2l+2w=80

So:

l+w = 80\div2

=40

l=40-w

Now, we can use substitution to find the value of w:

lw = 375

(40-w)w = 375

40w-w^2 = 375

375+w^2-40w = 0 (Quadratic equation)

(w-15)(w-25) = 0

∴ w = 15, 25

We can use substitution again to find the value of l

lw = 375

l=375\div w

=25,15

∵ Length usually refers to the longer side of a rectangle, ∴ length =25 inches and width =15 inches.

Hope this helps :)

8 0
2 years ago
Write a polynomial as the sum of the monomials and write it in standard form. For each of the above specify the degree of the re
klio [65]

Answer:

2b³ +2a -2c . . . . degree 3 polynomial

Step-by-step explanation:

The monomials are ...

... 4a . . . . degree 1 in a

... -5b·b² = -5b³ . . . . degree 3 in b

... -3c . . . . degree 1 in c

... 7b³ . . . . degee 3 in b (like term with -5b³)

... +c . . . . degree 1 in c (like term with -3c)

... -2a . . . . degree 1 in a (like term with 4a)

So, we have 3 pairs of like terms. The like terms can be combined by summing their coefficients.

The degree of the polynomial is that of the highest-degree term. (Here, the b³ term makes it a polynomial of degree 3.)

... 4a -2a = (4-2)a = 2a . . . . combining the "a" terms

... -5b³ +7b³ = (-5+7)b³ = 2b³ . . . . combining the b³ terms

... -3c +c = (-3 +1)c = -2c . . . . combining the "c" terms

In standard form, we write the highest-degree term first. Follwing terms are in order by decreasing degree. It is convenient, but perhaps not required, to then write the terms of the same degree in alphabetical order.

... = 2b³ +2a -2c . . . . a 3rd degree polynomial

7 0
2 years ago
SUZANNE rode her bike 15mph for 12 mins then rode 12mph for 20 mins how far did she ride
Anika [276]

Answer:

7 miles

Step-by-step explanation:

Distance = Rate times Time

Distance #1:  (15 mph)(12/60 hr) = 3 miles

Distance #2:  (12 mph)(20/60 hr) = 4 miles

Total distance ridden = 7 miles

7 0
2 years ago
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