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sergeinik [125]
3 years ago
14

3.6m by 1.8 m wall How many 6 cm by 6 cm pictures could fit on the wall?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0
(3.6*100)/6=60
(1.8*100)/6=30
60*30=1800
there are 1800 pictures could fit on the wall.
gladu [14]3 years ago
6 0

Answer:

1800 pictures could fit on the wall.

Step-by-step explanation:

If the area of a space is given as A and this space is to be filled by pictures of area A' then number of pictures will be = \frac{A}{A'}

Now we know area of wall is A and area of picture is A'.

Length and width of wall = 3.6×1.8 m

So area of the wall A = 3.6×1.8 = 6.48 m²

Dimensions of one picture = 6×6 cm Or 0.06×0.06 m

So are of one picture A' = 0.0036 m²

Therefore, Number of pictures on the wall = \frac{A}{A'} = \frac{6.48}{0.0036}=1800

Number of pictures required to cover the wall = 1800

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Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

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Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

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