This can be solved by finding the number of permutations of the eight performers who will all perform before the one who insists on being the last.
3.6m by 1.8 m wall How many 6 cm by 6 cm pictures could fit on the wall?
2 answers:
Answer:
1800 pictures could fit on the wall.
Step-by-step explanation:
If the area of a space is given as A and this space is to be filled by pictures of area A' then number of pictures will be =
Now we know area of wall is A and area of picture is A'.
Length and width of wall = 3.6×1.8 m
So area of the wall A = 3.6×1.8 = 6.48 m²
Dimensions of one picture = 6×6 cm Or 0.06×0.06 m
So are of one picture A' = 0.0036 m²
Therefore, Number of pictures on the wall = =
Number of pictures required to cover the wall = 1800
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Alright!
To solve, all we need to do is <em>subtract the area of the inner circle from the arear of the outer circle.</em>
But first, we need to find the area of both
Key equation: πr²
π = 3.14
Inner cirle area = π13²
π13² = 530.66
Outer cirle area = π21²
I got 21 by adding 8 and 13: both added together makes the radius of the larger circle
π21² = 1,385.74
Now let's <em>subtract. </em>
1,385.74 - 530.66 = 855.08
The area of the blue is = 855.08 yards²
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Part 2:
Hexagon with 6cm sides and an apothem of
The answer is C. 93.53