1) Line should be parallel to y = 3x+6, so slope of this line should be =3.
y=mx +b
y=3x +b
Now we have to find b (y-intercept), using the point (-10, 2.5).
2.5 = 3*(-10)+b
b=2.5+30=32.5
y=3x + 32.5
2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.
Now we have to find b (y-intercept), using the point (-16, -11).
y=(1/4)x +b
-11=(1/4)*(-16) + b
-11 = -4 +b
b = -7
y=(1/4)x - 7
N² - 49 = 0
<u> + 49 + 49</u>
n² = 49
n = <u>+</u>7
The solution to the problem is {7, -7}.
Answer:
I assume that the function is:

Now let's describe the general transformations that we need to use in this problem.
Reflection across the x-axis:
For a general function f(x), a reflection across the x-axis is written as:
g(x) = -f(x)
Reflection across the y-axis:
For a general function f(x), a reflection across the y-axis is written as:
g(x) = f(-x)
Then a reflection across the y-axis, and then a reflection across the x-axis is just:
g(x) = -(f(-x)) = -f(-x)
In this case, we have:

then:

Now we can graph this, to get the graph you can see below: