Let x be the degree of angle a.
Angle b: 20+3x
Angle c: 55+x
We know that all angles add up to 180 degrees.
180=x+(20+3x)+(55+x)
180= 5x+75
180-75=5x
105/5=x
21=x
Angle a: 21 degrees
Angle b: 20+3(21) => 83 degrees
Angle c: 21+55 => 76 degrees
Hope I helped :)
(-1,1)
This is because the solution is the point where the two lines meet.
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
Answer:
a) x=0, x=-10, x=11
Step-by-step explanation:
Just find the x- coordinates for when f(x) intersects g(x).
Answer:
A
Step-by-step explanation:
2b meaning two times the age then add three like the question says.
